Answer:
6m/s
Explanation:
the original momentum = mass x velocity = 8x (60+10) = 560
momentum after = mass x velocity of the school bag + mass x velocity of the boy = 10x20 + 60x A
200+60A = 560
A=6
Answer:
The smallest distance the student that the student could be possibly be from the starting point is 6.5 meters.
Explanation:
For 2 quantities A and B represented as
and 
The sum is represented as
For the the values given to us the sum is calculated as

Now the since the uncertainity inthe sum is 
The closest possible distance at which the student can be is obtained by taking the negative sign in the uncertainity
Thus closest distance equals
meters
Answer:
Farm = 98.1 [N]
Explanation:
To solve this problem we must draw the respective free body diagram, with the forces acting on the monkey. An analysis of the sums on the y-axis must be performed, in this axis the weight is acting down and the forces of both arms pulling up.
Weight is defined as the product of mass by gravitational acceleration.
W = m*g
where:
m = mass = 20 [kg]
g = gravity acceleration = 9.81 [m/s²]
W = 196.2 [N] (units of Newtons)
As this force points down, the force of both arms must go up, therefore each arm exerts a force of:
Farm = 196.2 / 2
Farm = 98.1 [N]