Answer:
pH of the final solution = 9.15
Explanation:
Equation of the reaction: HCl + NH₃ ----> NH₄Cl
Number of moles of NH₃ = molarity * volume (L)
= 0.4 M * (300/1000) * 1 L = 0.12 moles
Number of moles of HCl = molarity * volume (L)
= 0.3 M * (175/1000) * 1 L = 0.0525 moles
Since all he acid is used up in the reaction, number of moles of acid used up equals number of moles of NH₄Cl produced
Number moles of NH₄Cl produced = 0.0525 moles
Number of moles of base left unreacted = 0.12 - 0.0525 = 0.0675
pOH = pKb + log([salt]/[base])
pKb = -logKb
pOH = -log (1.8 * 10⁻⁵) + log (0.0525/0.06755)
pOh = 4.744 + 0.109
pOH = 4.853
pH = 14 - pOH
pH = 14 - 4.853
pH = 9.15
Therefore, pH of the final solution = 9.15
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2O3→3O2
The number of moles of O2 that are produced when 0.50 moles of O3(g) reacted is 0.75 moles
calculation and explanation
2 moles of O3(ozone) react to give 3 moles of O2 (oxygen gas,therefore the reacting ratio between O3 :O2 is 2:3
if 0.50 moles of O3 reacted then,by use of reacting ratio (2:3) find the moles of O2 produced
That is 0.50 x3/2 = 0.75 moles
Correct Answer: First Option
An oxidizing agent causes the oxidation of the other atom/element by itself being reduced. In simple words we can state that oxidizing agent gains electrons from the other atom/element i.e. the other atom loses electrons.
From the given options we have to find in which of them electrons are being removed. When the electrons are removed, the number of protons in the atom will be more than the number of electrons. As a result the net charge on the atom will be positive.
First option lists such a change. Initially charge on Al is neutral, 3 electrons are removed and it get +3 charge. This shows that Al is being oxidized, so it needs an oxidizing agent.
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