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julia-pushkina [17]
3 years ago
5

Predict the products of the reaction below. that is, complete the right-hand side of the chemical equation. be sure your equatio

n is balanced and contains state symbols after every reactant and product. \chem;[h]\chem;[br](1[\chemwrong;[aq]]1)+[[\chem;[h]]_[2]]\chem;[o](1[\chemwrong;[l]]1)\chemarrow;[]
Chemistry
1 answer:
kkurt [141]3 years ago
8 0
The equation is as follow,

<span>                                  HBr </span>₍aq₎  +  H₂O ₍l₎    →

Solution:
             HBr being strong acid with Ka value of 1.0 × 10⁹. When HBr is added to water, water acts as a base and HBr acts as a acid. Water picks the proton (H⁺) from HBr and converts into Conjugate acid (H₃O⁺) ahile HBr is converted into Conjugate Base (Br⁻) after loosing proton. The equation for this reaction is as follow,

                      HBr ₍aq₎  +  H₂O ₍l₎    →    H₃O⁺ ₍aq₎  +  Br⁻ ₍aq₎
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Is francium found in nature or lab?
ddd [48]

Answer:

It was the last element first discovered in nature, rather than by synthesis. Outside the laboratory, francium is extremely rare, with trace amounts found in uranium and thorium ores, where the isotope francium-223 continually forms and decays

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Answer:

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Explanation:

8 0
3 years ago
What is the molar mass of Fe(NO3)2?
motikmotik
I believe that the molar mass is 342.34g/mol
5 0
3 years ago
CH4 + 202 → CO2 + 2H2O<br> How many grams of O2 needed to produce 36 grams of H2O?
Kipish [7]
<h3>Answer:</h3>

64 g O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced]   CH₄ + 2O₂ → CO₂ + 2H₂O

[Given]   36 g H₂O

[Solve]   x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol O₂ → 2 mol H₂O

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mas of H - 1.01 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up conversion:                     \displaystyle 36 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{2 \ mol \ O_2}{2 \ mol \  H_2O})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})
  2. Divide/Multiply [Cancel Units]:                                                                       \displaystyle 63.929 \ g \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

63.929 g O₂ ≈ 64 g O₂

8 0
3 years ago
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In which group of teh modern periodic table are there very reactive metals and very reactive non metals?​
Rufina [12.5K]

Metals :-

Group 1A - Alkali metals ( highly reactive metals)

Non-metals :-

Group 17 - Halogens ( highly reactive non-metals )

5 0
4 years ago
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