Predict the products of the reaction below. that is, complete the right-hand side of the chemical equation. be sure your equatio
n is balanced and contains state symbols after every reactant and product. \chem;[h]\chem;[br](1[\chemwrong;[aq]]1)+[[\chem;[h]]_[2]]\chem;[o](1[\chemwrong;[l]]1)\chemarrow;[]
Solution: HBr being strong acid with Ka value of 1.0 × 10⁹. When HBr is added to water, water acts as a base and HBr acts as a acid. Water picks the proton (H⁺) from HBr and converts into Conjugate acid (H₃O⁺) ahile HBr is converted into Conjugate Base (Br⁻) after loosing proton. The equation for this reaction is as follow,
