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jasenka [17]
4 years ago
7

E85 fuel is a mixture of 85% ethanol and 15% gasoline by volume. What mass in kilograms of E85 (d = 0.758 g/mL) can be contained

in a 14.0-gal tank?
Chemistry
2 answers:
alexandr402 [8]4 years ago
7 0

The answer is: mass is 40.17 kilograms.

d = 0.758 g/mL; density of fuel.

V = 14.0 gal; volume.

A gallon is a unit of volume in both the US customary and imperial systems of measurement. The US gallon is defined as 231 cubic inches (3.785 liters).

1 gal = 3785.41 mL.

V = 14 gal · 3785.41 mL:

V = 52995.74 mL.

m = 52995.74 mL · 0.758 g/mL.

m = 40170.77 g; mass of fuel.

m = 40170.77 g ÷ 1000 g/kg.

m = 40.17 kg.

gizmo_the_mogwai [7]4 years ago
4 0

Answer : The mass of E85 fuel is, 40.166 kilogram.

Solution : Given,

Volume of E85 fuel = 14gallon=14\times 3785.41ml/gal=52990ml

(1gallon=3785.41ml)

Density of E85 fuel = 0.758 g/ml

Formula used :

\text{Mass of E85 fuel}=\text{Density of E85 fuel}\times \text{Volume of E85 fuel}

Now put all the given values in this formula, we get

\text{Mass of E85 fuel}=0.758g/ml\times 52990ml=40166.42g=40.166Kg

(1Kg=1000g)

Therefore, the mass of E85 fuel is, 40.166 kilogram.

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<h3>Further explanation</h3>

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<h3>What is the electron dot diagram?</h3>

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The electron dot diagram for the oxygen atom is drawn as follows:

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7 0
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<span>Answer is: pH of solution of sodium cyanide is 11.3.
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Kb = [HCN] · [OH</span>⁻] / [CN⁻<span>].
[HCN] · [OH</span>⁻<span>] = x.
[CN</span>⁻<span>] = 0.021 M - x..
2.04·10</span>⁻⁵<span> = x² / (0.021 M - x).
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pH = 14 - 2.70 = 11.3.</span>

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