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jasenka [17]
4 years ago
7

E85 fuel is a mixture of 85% ethanol and 15% gasoline by volume. What mass in kilograms of E85 (d = 0.758 g/mL) can be contained

in a 14.0-gal tank?
Chemistry
2 answers:
alexandr402 [8]4 years ago
7 0

The answer is: mass is 40.17 kilograms.

d = 0.758 g/mL; density of fuel.

V = 14.0 gal; volume.

A gallon is a unit of volume in both the US customary and imperial systems of measurement. The US gallon is defined as 231 cubic inches (3.785 liters).

1 gal = 3785.41 mL.

V = 14 gal · 3785.41 mL:

V = 52995.74 mL.

m = 52995.74 mL · 0.758 g/mL.

m = 40170.77 g; mass of fuel.

m = 40170.77 g ÷ 1000 g/kg.

m = 40.17 kg.

gizmo_the_mogwai [7]4 years ago
4 0

Answer : The mass of E85 fuel is, 40.166 kilogram.

Solution : Given,

Volume of E85 fuel = 14gallon=14\times 3785.41ml/gal=52990ml

(1gallon=3785.41ml)

Density of E85 fuel = 0.758 g/ml

Formula used :

\text{Mass of E85 fuel}=\text{Density of E85 fuel}\times \text{Volume of E85 fuel}

Now put all the given values in this formula, we get

\text{Mass of E85 fuel}=0.758g/ml\times 52990ml=40166.42g=40.166Kg

(1Kg=1000g)

Therefore, the mass of E85 fuel is, 40.166 kilogram.

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san4es73 [151]

Answer:

4.94g of material

Explanation:

Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:

Kp = <em>8 = Concentration in Ethyl acetate / Concentration in water</em>

100mL of a 5% solution contains 5g of material in 100mL of water. Thus:

8 = X / 100mL / (5g-X) / 100mL

<em>Where X is the amount of material in grams that comes to the organic phase.</em>

8 = X / 100mL / (5g-X) / 100mL

8 = 100X / (500-100X)

4000 - 800X = 100X

4000 = 900X

4.44g = X

<em>Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.</em>

And will remain 5g-4.44g = 0.56g.

In the second extraction:

8 = X / 100mL / (0.56g-X) / 100mL

8 = 100X / (56-100X)

448 - 800X = 100X

448 = 900X

0.50g = X

<em>In the second extraction, you will extract 0.50g of material</em>

Thus, after the two extraction you will lost:

4.44g + 0.50g = <em>4.94g of material</em>

<em></em>

6 0
3 years ago
Brainliest for an answer!
Degger [83]

The volume of H₂ : = 15.2208 L

<h3>Further explanation</h3>

Given

Reaction

2 As (s) + 6 NaOH (aq) → 2 Na₃AsO₃ (s) + 3 H₂ (g)

34.0g of As

Required

The volume of H₂ at STP

Solution

mol As (Ar = 75 g/mol) :

= mass : Ar

= 34 g : 75 g/mol

= 0.453 mol

From the equation, mol ratio As : H₂ = 2 : 3, so mol H₂ :

=3/2 x mol As

=3/2 x 0.453

= 0.6795

At STP, 1 mol = 22.4 L, so :

= 0.6795 x 22.4 L

= 15.2208 L

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3 years ago
Pure research becomes ___ when scientists develop a hypothesis based on the data and try to solve a specific problem
Inessa05 [86]

Answer:

The answer is <u>applied research</u>

Explanation:

Pure research becomes <u>applied research</u> when scientists develop a hypothesis based on the data and try to solve a specific problem.

This is because the pure research try to understand, predict or explain the behavior of different phenomena <em>(the data)</em> while the applied research try to develop new technologies or methods (<em>hypothesis)</em> to take part, intervene and/or create changes on these phenomena and solve a <em>specific problem.</em>

5 0
3 years ago
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Blababa [14]

Answer: 1. Ethylene is a stable molecule with two carbon atoms connected by a double bond. Polyethylene is made by the reaction of multiple ethylene molecules in the presence of a catalyst.

2. The term “plastics” includes materials composed of various elements such as carbon, hydrogen, oxygen, nitrogen, chlorine, and sulfur.

3. Polyethylene (PE) is made by the reaction of multiple ethylene molecules in the presence of catalysts to break the double bond and connect the carbon atoms into a chain . The longer the chain, the higher the molecular weight. Polymers can have molecular weights in the millions.

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3 years ago
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MatroZZZ [7]

Answer:

D. 1.48atm

Explanation:

Van der waals equation is given as:

(P +an²/v²) (v - nb) = nRT

Where;

P = pressure (atm)

V = volume (L)

R = gas constant (0.0821 Latm/molK)

a and b = gas constant specific to each gas

T = temperature (K)

n = number of moles

According to the given information; V = 22.4L, T = 0.00°C (273.15K), R = 0.0821 Latm/molK, a = 6.49L^2-atm/mol^2, b = 0.0562 L/mol, n = 1.5mol

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(P + 6.49 × 1.5²/22.4²) (22.4 - 1.5×0.0562) = 1.5 × 0.0821 × 273.15

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P = 32.989/22.316

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6 0
3 years ago
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