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3 years ago

9

Does the light bulb filament appear to have a constant resistance (constant ratio of voltage to current)?

2 answers:

Leviafan [203]3 years ago

6 0

Answer:

No...The resistance of the filament isn't constant

Explanation:

It is because the filament to light up the resistance is always constantly increasing that will ultimately causes increase in the temperature of filament and eventually it lights up. The resistance always keep on increasing as the current in the filament is going to increase and vice versa.

NeX [460]3 years ago

5 0

Answer:

Does the light bulb filament appear to have a constant resistance (constant ratio of voltage to current)?

The Answer is "NO"

The light bulb filament does not have a constant resistance.

Explanation:

Resistance is one of the basic principles of Ohm’s law, resistance is the opposition to current caused by a resistor. The opposition is towards the flow of electric current. The value of resistance of a conductor depends upon: The thickness, the material from which the conductor is made, the temperature at which it operates, and, the length of the conductor.

The filament is the part of the light bulb that produces light. Filaments is a thin tungsten wire in the light bulb which resists the flow of electrons. Filament heats up when an electric current passes through it, and produces light as a result.

The resistance of the filament is not constant, rather, it increases with increased current. If extreme currents are applied to wires, they heat up, change their resistances, in turn, the resistance of a lamp increases as the temperature, and, as the current in a circuit goes up, the voltage goes up too. The relationship between the current flowing through a filament lamp and the voltage across it is not directly proportional.

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Suppose a 65.5 kg gymnast climbs a rope. What is the tension in the rope if she climbs at a constant speed

natali 33 [55]

The tension in the rope when the gymnast climbs it at constant speed is 641.9 N.

Given:

Mass of gymnast, m = 65.5 kg

The speed 'v' of gymnast is constant

Solution:

Consider the free-body diagram of the system as shown below.

Balancing forces along the vertical axis we get:

ΣFy = 0

Thus, we get:

F = ma - (1)

where, m is mass of gymnast

a is acceleration of gymnast (a = 0m/s², as the speed is constant)

Also,

F = T - mg -(2)

where, T is tension in the rope

g is acceleration due to gravity

Equating (1) & (2), we get:

ma = T - mg

Re-arranging the equation, we get:

T = m(a+g)

Applying values in above equation we get:

T = (65.5 kg)(0 m/s²+9.8 m/s²)

T = 641.9 N

Therefore, the tension in the rope when the gymnast climbs it at constant speed is 641.9 N.

Learn more about tension here:

<u>brainly.com/question/14294135</u>

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7 0

2 years ago

Part 1 - Basic Equations

bearhunter [10]

Answer:

1. λ = 2 L, 2. v = 2L f₁ , 3. v = √ T /μ², 4. μ = 2,287 10⁻³ kg / m , 5. Δv / v = 0.058 , 6. Δμ / μ = 0.12 , 7. Δ μ = 0.3 10⁻³ kg / m ,

8. μ = (2.3 ±0.3) 10⁻³ kg / m

Explanation:

The speed of a wave is

v = λ f 1

Where f is the frequency and λ the wavelength

The speed is given by the physical quantities of the system with the expression

v = √ T /μ² 2

1) The fundamental frequency of a string is when at the ends we have nodes and a maximum in the center, therefore this is

L = λ / 2

λ = 2 L

2) For this we substitute in equation 1

v = 2L f₁

3) let's clear from equation 2

The speed of a wave is

v = λ f₁

Where f is the frequency and Lam the wavelength

The speed is given by the physical quantities of the system with the expression

v = √ T /μ² 2

4) linear density is

μ = T / (2 L f₁)²

μ = 5.08 / (2 0.812 29.02)²

μ = 2,287 10⁻³ kg / m

We maintain three significant length figures, so the result is reduced to

μ = 2.29 10⁻³ kg / m

5) the speed of the wave is

v = 2 L f₁

The fractional uncertainty is

Δv / v = ΔL / L + Δf₁ / F₁

Δv / v = 0.02 / 0.812 + 1 / 29.02

Δv / v = 0.024 + 0.034

Δv / v = 0.058

6) the equation for linear density is

μ = T / (2 L f₁)²

Δμ / μ = 2 ΔL / L + 2Δf₁ / f₁

The tension is an exact value therefore its uncertainty is zero ΔT = 0

Δμ / μ = 2 0.02 / 0.812 + 2 1 / 29.02

Δμ / μ = 0.12

7) absolute uncertainty

Δ μ = $e_{r}$ μ

Δ μ = 0.12 2.29 10⁻³ kg / m

Δ μ = 0.3 10⁻³ kg / m

8)

μ = (2.3 ±0.3) 10⁻³ kg / m

8 0

3 years ago

Which of the following processes could NOT be used to separate dissolved particles from the liquid in a solution? *

DIA [1.3K]

Answer:

Vaporation

Explanation:

In the vaporization or boiling, the passage of particles from the liquid state to the gaseous state occurs completely

5 0

4 years ago

Read 2 more answers

What is the force of gravitational attraction between an object with a mass of 100 kg and another object that has a mass of 300

Leokris [45]

Answer:

5 x 10⁻⁷N

Explanation:

Given parameters:

Mass of object 1 = 100kg

Mass of object 2 = 300kg

Distance = 2m

Unknown:

Force of gravitational attraction between the objects = ?

Solution:

Newton's law of universal gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

From Newton's law of universal gravitation we derive an expression:

Fg = $\frac{Gm_{1} m_{2} }{r^{2} }$

G is the universal gravitation constant = 6.67 x 10⁻¹¹

m is the mass

r is the distance between the bodies

Now insert the parameters and solve;

Fg = 6.67 x 10⁻¹¹ x $\frac{100 x 300}{2^{2} }$ = 5 x 10⁻⁷N

7 0

3 years ago

A physics demo launches a ball horizontally while dropping a second ball vertically at exactly the same time. 1) which ball hits

Simora [160]

Answer:

Both balls will hit the ground at the same time

Explanation:

The factor which leads to ball falling is the gravity acting on the ball;

The motions along the path of both balls are independent and both balls will obey the following illustration

Using the third equation of motion

s = ut + ½at²

Where s = distance covered by both balls.

u = initial velocity of both balls. Since both balls start from rest, u = 0m/s

a = acceleration; and it's equal to acceleration due to gravity.

a = g

By substituton

s = 0 * t + ½gt²

s = 0 + ½gt²

s = ½gt²

Make t the subject of formula

gt² = 2s

t² = 2s/g

t = ±√(2s/g)

But time can't be less than 0 (in other words, negative)

So,

t = √(2s/g)

It'll take both balls √(2s/g) time to hit the floor

6 0

3 years ago

Read 2 more answers