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Llana [10]
2 years ago
5

a man is trying to pull a box a distance of 3 m with a force of 20 N that makes a 35º with the horizontal.

Physics
1 answer:
Ivanshal [37]2 years ago
5 0

Answer:

34.4Joules

Explanation:

Complete question

a man is trying to pull a box a distance of 3 m with a force of 20 N that makes a 35º with the horizontal. Find the workdone

Work done = Fdsin theta

Force F = 20N

distance d = 3m

theta = 35 degrees

Substitute

Workdone = 20(3)sin 35

Workdone = 60sin35

Workdone = 34.4Joules

Hence the workdone by the man is 34.4Joules

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6 0
3 years ago
A camera is equipped with a lens with a focal length of 34 cm. When an object 2.4 m (240 cm) away is being photographed, what is
puteri [66]

Answer:

The magnification is -6.05.

Explanation:

Given that,

Focal length = 34 cm

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We need to calculate the distance of the object

\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}

Where, u = distance of the object

v = distance of the image

f = focal length

Put the value into the formula

\dfrac{1}{u}=\dfrac{1}{34}-\dfrac{1}{240}

\dfrac{1}{u}=\dfrac{103}{4080}

u =\dfrac{4080}{103}

The magnification is

m = \dfrac{-v}{u}

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m = -6.05

Hence, The magnification is -6.05.

6 0
3 years ago
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BaLLatris [955]

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3 0
3 years ago
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44 = m * 9.81m/s^2

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3 years ago
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eimsori [14]

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In an inverse relationship, when one variable increases, the other variable decreases.

Explanation:

Hope this helps! ^^

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3 years ago
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