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Llana [10]
2 years ago
5

a man is trying to pull a box a distance of 3 m with a force of 20 N that makes a 35º with the horizontal.

Physics
1 answer:
Ivanshal [37]2 years ago
5 0

Answer:

34.4Joules

Explanation:

Complete question

a man is trying to pull a box a distance of 3 m with a force of 20 N that makes a 35º with the horizontal. Find the workdone

Work done = Fdsin theta

Force F = 20N

distance d = 3m

theta = 35 degrees

Substitute

Workdone = 20(3)sin 35

Workdone = 60sin35

Workdone = 34.4Joules

Hence the workdone by the man is 34.4Joules

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Density = Mass divided by Volume
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Which statement best describes a device that has a high energy efficiency? Its ratio of energy absorbed to energy released is hi
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Answer:

It wastes little energy

Explanation:

  • The efficiency of a machine refers to the ratio of work output to the work input as a percentage.
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An empty parallel plate capacitor is connected between the terminals of a 18.8-V battery and charges up. The capacitor is then d
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Answer:

p.d' = 37.6 V

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New Capacitor C_1=C_2/2

Generally the equation for Capacitor capacitance is mathematically given by

C=\frac{eA}{d}

Generally the equation for New p.d' is mathematically given by

 C_2V=C_1*p.d'

  p.d' = 2V

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7 0
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A sprinter has a mass of 80 kg and a KE of 4000 J. What is the sprinter’s speed?
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8 0
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A car and a lorry are about to collide. When they collide the two vehicles become tightly locked together. The lorry is going at
BartSMP [9]

Answer:

The speed of the vehicles immediately after the collision is 5.84 m/s.

Explanation:

The speed of the vehicles after the collision can be found by conservation of linear momentum:

p_{i} = p_{f}

m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}

Where:

m₁: is the mass of the car = 0.5 ton = 500 kg

m₂: is the mass of the lorry = 9.5 ton = 9500 kg

v_{1_{i}}: is the initial speed of the car = 40 km/h = 11.11 m/s

v_{2_{i}}: is the initial speed of the lorry = 20 km/h = 5.56 m/s

v_{1_{f}}: is the final speed of the car =?

v_{2_{f}}: is the final speed of the lorry =?    

Since the two vehicles become tightly locked together after the collision v_{1_{f}} = v_{2_{f}}:

m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = v(m_{1} + m_{2})

v = \frac{m_{1}v_{1_{i}} + m_{2}v_{2_{i}}}{m_{1} + m_{2}} = \frac{500 kg*11.11 m/s + 9500 kg*5.56 m/s}{500 kg + 9500 kg} = 5.84 m/s

Therefore, the speed of the vehicles immediately after the collision is 5.84 m/s.

I hope it helps you!  

8 0
2 years ago
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