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Karo-lina-s [1.5K]
3 years ago
6

A dog walks 26m, East, 29m, West, and 7m, East. What is his displacement?

Physics
1 answer:
sergeinik [125]3 years ago
7 0

Answer:

4m East

Explanation:

26-29= -3 (so that means 3m west)

-3+7= 4 (so 4m East)

hope it helps

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If a 50 W light bulb and a 90 W light bulb operate from 120 V, which bulb has a greater current in it?
PIT_PIT [208]
The 50 W bulb would have a greater current than the 90 W bulb
8 0
3 years ago
Suppose a piece of food is on the edge of a rotating microwave oven plate. Does it experience nonzero tangential acceleration, c
Rus_ich [418]

Answer:

Explanation:

(a) When the plate starts to spin:

Its angular velocity increases, so the angular acceleration is non zero. As the direction of velocity keeps on changing every instant so the linear acceleration is also non zero.

(b) When the plate rotates at constant angular velocity:

Its angular velocity is constant so the angular acceleration is zero. As the direction of velocity keeps on changing every instant so the linear acceleration is also non zero.

(c) When the plate sows to halt:

Its angular velocity decreases, so the angular acceleration is non zero( but negative). As the direction of velocity keeps on changing every instant so the linear acceleration is also non zero.

4 0
3 years ago
If two objects of the same size move through the air at different speeds, which encounters the greater air resistance?a. The fas
blagie [28]

Answer:

Option A is correct.

(The faster object encounters more resistance)

Explanation:

Option A is correct. (The faster object encounters more resistance)

Air resistance depends on various factors:

  • Speed of the object
  • Cross-sectional area of the object
  • Shape of the object

Formula:

F=\frac{1}{2}C_d\rho A v^{2}

As the speed of the object increases the amount of Air resistance/drag increases on the object, as the above formula shows direct relation between Air resistance/drag and velocity i.e F ∝ v^2.

6 0
3 years ago
Bumper cars A and B undergo a collision during which the momentum of the combined system is conserved.
dexar [7]

Answer:

1. P⃗ A,i+P⃗ B,i=P⃗ A,f+P⃗ B,f

Explanation:

Collision occurs when two bodies moving at different velocities exert force on each other through colliding. Collision can either be elastic or inelastic.

For elastic collision, both energy and momentum of the bodies is conserved i.e they separates after collision.

For inelastic collision, only momentum is conserved but not energy. The body sticks together after colliding and moves with a common velocity.

According law of conservation of momentum which states that the sum or momentum of two bodies before collision is equal to the momentum of the bodies after collision.

Given two bumper cars A and B that undergoes collision during which momentum is conserved, the type of collision that exists between the bumpers is inelastic collision

.

If initial momentum of A is PiA and initial momentum of B is PiB, the sum of their momentum before collision is expressed as;

PiA + PiB ... (1)

If final momentum of A is PfA and initial momentum of B is PfB, the sum of their momentum after collision is expressed as;

PfA+PfB ... (2)

According to the law, equation 1 is equal to equation 2

The fore the formula that states the law is expressed as;

PiA + PiB = PfA+PfB

5 0
3 years ago
The force of repulsion between to like charge table tennis balls is 8.2 X 10 ^-7 N if the charge on the two objects a 6.7 X10^-9
Svetllana [295]

Answer:

0.702 m

Explanation:

The magnitude of the electrostatic force between two charged objects is given by Coulomb's Law:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the objects

And the force is:

- Attractive if the two charges have opposite signs (+-)

- Repulsive if the two charges have same sign (++ or --)

In this problem we have:

F=8.2\cdot 10^{-7}N is the force between the two balls

q_1 = q_2 = 6.7\cdot 10^{-9}C is the charge on each ball

Solving for r, we find the separation between the balls:

r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(9\cdot 10^9)(6.7\cdot 10^{-9})^2}{8.2\cdot 10^{-7}}}=0.702 m

5 0
3 years ago
Read 2 more answers
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