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Vaselesa [24]
3 years ago
5

Distinguish between metals, ionic compounds, and covalent compounds using information about the physical properties of a compoun

d. Distinguish between metals, ionic compounds, and covalent compounds using the empirical formula of a compound.
Chemistry
1 answer:
sineoko [7]3 years ago
7 0

Distinguish between metals, ionic compounds, and covalent compounds using information about the physical properties of a compound.

Metal Compounds:

  • Metal compounds have very High melting and boiling points
  • They are good Conductors of heat and electricity
  • They can be converted into different shapes without any breakage.
  • They are ductile and magnetic.

Ionic compounds

  • Ionic compounds exist in a crystalline structure that is stable. Hence, they higher melting and boiling points than covalent compounds.
  • They don't conduct electricity when they are as ionic compounds. But, when they are dissolved in water the solution becomes conductor of electricity.
  • These compounds exist as solids only.
  • These compounds are Non magnetic.

Covalent compounds

  • They have lower belting and boiling points when compared to ionic bonds.
  • Covalent compounds are non conductor of electricity.
  • They can take any form like liquid, solid or gas.
  • They are  Non magnetic.

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What is the mass of Al₂O3 that will contain 10 kg of aluminium?​
Oksanka [162]

Answer:

1 mole of Al2O3 = 102 grams

1 mole of Al2 = 54 grams

102 grams of Al2O3 contains = 54 gram of Al2

10kg of Al2O3 contains = (54/102)*10000g Al2

= 5294.11 g Al2 or 5.29411 kg

5 0
2 years ago
Read 2 more answers
7. What is the voltage when the resistance is 6 ohms and the current is 8 amps?
vivado [14]

Answer:

48 volts

Explanation:

Voltage (E) = Current (I) x Resistance (R), or E = IR.

4 0
3 years ago
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A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum ch
amm1812

Answer:

2000 millimoles of AlCl₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 1.8 L

Molarity of solution = 1.1 mol /L

Millmole of AlCl₃ =?

Next, we shall determine the number of mole of AlCl₃ in the solution.

This can be obtained as follow:

Volume of solution = 1.8 L

Molarity of AlCl₃ solution = 1.1 mol /L

Number of mole of AlCl₃ =?

Molarity = mole /Volume

1.1 = Number of mole of AlCl₃ / 1.8

Cross multiply

Number of mole of AlCl₃ = 1.1 × 1.8

Number of mole of AlCl₃ = 1.98 moles

Finally, we shall convert 1.98 moles to millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

1.98 mole = 1.98 mole × 1000 millimoles / 1 mole

1.98 mole = 1980 millimoles

1.98 mole ≈ 2000 millimoles

Thus, the chemist added 2000 millimoles of AlCl₃

7 0
3 years ago
Does this sound good so far
bogdanovich [222]
I think it looks good but some grammars are wrong i suggest trying to put it on grammarly and just check it out its just my suggestion and not doing this for points so you can delete this if it doesnt help
4 0
3 years ago
A compound is determined to have the empirical formula C2OH4. If the molar mass of the compound is 132 g/mol, determine the mole
8_murik_8 [283]

Answer: The molecular formula will be C_6O_3H_{12}

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

Empirical weight of C_2OH_{4} is 12\times 2+16\times 1+1\times 4=44g

Molecular mass of compound is = 132 g

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{132}{44}=3

The molecular formula will be=3\times C_2OH_4=C_6O_3H_{12}

5 0
3 years ago
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