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Vaselesa [24]
3 years ago
5

Distinguish between metals, ionic compounds, and covalent compounds using information about the physical properties of a compoun

d. Distinguish between metals, ionic compounds, and covalent compounds using the empirical formula of a compound.
Chemistry
1 answer:
sineoko [7]3 years ago
7 0

Distinguish between metals, ionic compounds, and covalent compounds using information about the physical properties of a compound.

Metal Compounds:

  • Metal compounds have very High melting and boiling points
  • They are good Conductors of heat and electricity
  • They can be converted into different shapes without any breakage.
  • They are ductile and magnetic.

Ionic compounds

  • Ionic compounds exist in a crystalline structure that is stable. Hence, they higher melting and boiling points than covalent compounds.
  • They don't conduct electricity when they are as ionic compounds. But, when they are dissolved in water the solution becomes conductor of electricity.
  • These compounds exist as solids only.
  • These compounds are Non magnetic.

Covalent compounds

  • They have lower belting and boiling points when compared to ionic bonds.
  • Covalent compounds are non conductor of electricity.
  • They can take any form like liquid, solid or gas.
  • They are  Non magnetic.

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Which of the following solvents would be the best to separate a mixture containing benzoic acid, 2,4-dinitrobenzoic acid, and 2,
KatRina [158]

Answer:

The correct option is Methylene chloride

Explanation:

Methylene chloride or Dichloromethane has an organic formula of CH2CL2. it is commonly used as solvent, it is very volatile and dissolves many organic compounds including a mixture containing benzoic acid, 2,4-dinitrobenzoic acid, and 2,4,6-trinitrobenzoic acid. It is colorless, has a chloroform like odor and Miscible in ethyl acetate, alcohol, hexanes, benzene, CCl4, diethyl ether, CHCl3.

4 0
3 years ago
He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o
Xelga [282]

Answer : The activation energy of the reaction is, 17.285\times 10^4kJ/mole

Solution :  

The relation between the rate constant the activation energy is,  

\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = initial rate constant = 4.55\times 10^{-5}L/mole\text{ s}

K_2 = final rate constant = 8.75\times 10^{-3}L/mole\text{ s}

T_1 = initial temperature = 195^oC=273+195=468K

T_2 = final temperature = 258^oC=273+258=531K

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]

Ea=17.285\times 10^4kJ/mole

Therefore, the activation energy of the reaction is, 17.285\times 10^4kJ/mole

8 0
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Explanation:

hope it helps

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