How much is 1 mole of salt or NaCl
1 answer:
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4.48
pH=pKa+log([A-/HA])
25% deprotonated tells us that A- is .25 and that the rest (75% is protonated) thats .75.
4 = pKa + log
4 - log = pKa
4.48=pKa
pH=pKa+log([A-/HA])
25% deprotonated tells us that A- is .25 and that the rest (75% is protonated) thats .75.
4 = pKa + log
4 - log
4.48=pKa
Answer : The temperature of the air in the tire is, 341 K
Explanation :
Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.
or,
where,
= initial pressure = 198 kPa
= final pressure = 225 kPa
= initial temperature =
= final temperature = ?
Now put all the given values in the above equation, we get:
Therefore, the temperature of the air in the tire is, 341 K