Answer:
The molar concentration of this solution is 0.0463 mol/L
Explanation:
Step 1 : Data given
Mass of a nonelectrolyte solute = 2.69 grams
Volume of water = 345 mL = 0.345 L
Temperature = 26.0°CC = 273 + 26 = 299 K
The osmotic pressure = 863 torr
⇒ 863torr /760 = 1.13553 atm
Step 2: Calculate the molar concentration of this solution
Π = i*M*R*T
⇒with Π = the osmotic pressure = 1.13553 atm
⇒with i = the van't Hoff factor of the nonelectrolyte solute = 1
⇒with M = the molar concentration = TO BE DETERMINED
⇒with R = the gas constant = 0.08206 L*atm/mol*K
⇒with T = the temperature = 299 K
1.13553 atm = 1 * M * 0.08206 L*atm/mol*K * 299 K
M = 1.13553 / (0.08206*299)
M = 0.0463 mol/L
The molar concentration of this solution is 0.0463 mol/L
