All categories

3 years ago

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution

Chemistry

2 answers:

OLEGan [10]3 years ago

7 0

Answer:

16 Molarity

Step-by-step:

M= mols/L

M= 8mols/.5L

M= 16 Molarity

Leno4ka [110]3 years ago

5 0

Answer:

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

$Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}$

Moles of NaOH = 8 moles

Volume of the solution = 0.5 L

$Molarity=\frac{8 mol}{0.5 L}=16.0 M$

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.

You might be interested in

what would be the effect on the properties of the water molecule if oxygen and hydrogen had equal electronegativity?

ohaa [14]

Answer:

It would no longer be a polar molecule with a slightly positive and slightly negative ends. It then would not be able to dissolve ionic salts or polarized organic compounds such as sugar.

Explanation:

7 0

3 years ago

If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?

myrzilka [38]

Answer:

Mass of original sample = 100 g

Explanation:

Half life of cesium-137 = 30.17 years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{30.17}\ year^{-1}$

The rate constant, k = 0.02297 year⁻¹

Time = 90.6 years

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Initial concentration $[A_0]$ = ?

Final concentration $[A_t]$ = 12.5 grams

Applying in the above equation, we get that:-

$12.5\ g=[A_0]e^{-0.02297\times 90.6}$

$[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g$

<u>Mass of original sample = 100 g</u>

8 0

3 years ago

Frrrreeeeeee point freeeeee

ahrayia [7]

Answer:

Ok the answer is 345

Explanation:

7 0

2 years ago

Ammonia can be produced in the laboratory by heating ammonium chloride

AnnyKZ [126]

Answer:

Mass = 2.89 g

Explanation:

Given data:

Mass of NH₄Cl = 8.939 g

Mass of Ca(OH)₂ = 7.48 g

Mass of ammonia produced = ?

Solution:

2NH₄Cl + Ca(OH)₂ → CaCl₂ + 2NH₃ + 2H₂O

Number of moles of NH₄Cl:

Number of moles = mass/molar mass

Number of moles = 8.939 g / 53.5 g/mol

Number of moles = 0.17 mol

Number of moles of Ca(OH)₂ :

Number of moles = mass/molar mass

Number of moles = 7.48 g / 74.1 g/mol

Number of moles = 0.10 mol

Now we will compare the moles of ammonia with both reactant.

NH₄Cl : NH₃

2 : 2

0.17 : 0.17

Ca(OH)₂ : NH₃

1 : 2

0.10 : 2/1×0.10 = 0.2 mol

Less number of moles of ammonia are produced by ammonium chloride it will act as limiting reactant.

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.17 mol × 17 g/mol

Mass = 2.89 g

6 0

3 years ago

Which molecule in plants cells first captures the radiant energy from sunlight?

melisa1 [442]

Answer:

c tell me if im wrong:)

Explanation:

7 0

2 years ago