The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution
2 answers:
Answer:
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.
Explanation:
Molarity of the solution is the moles of compound in 1 Liter solutions.
Moles of NaOH = 8 moles
Volume of the solution = 0.5 L
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.
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Answer:- solution boiling point = 102.23 degree C (102 degree C with three sig figs).
Solution:- When a non volatile solute is added to a solvent then boiling point increases. Elevation in boiling point is directly proportional to the molality of the solution.
The equation is:
where, is the elevation in boiling point, i is the Van't hoff factor,
is the molal elevation constant and m is the molality.
Value of i is 1 as ethylene glycol is a covalent molecule that does not break to give ions. for water is
.
We can calculate the molality from the given grams of ethylene glycol and liters of water as molality is moles of solute per kg of solvent.
Molar mass of ethylene glycol is 62 gram per mol and density of water is 1.00 kg per liter.
= 2.50 kg
Let's calculate the moles of ethylene glycol.
= 10.9 mol
molality of the solution =
= 4.36m
Let's plug in the values in the equation we have on the top for elevation in boiling point.
=
Boiling point of pure water is 100 degree C. So, the boiling point of the solution = 100 + 2.23 = 102.23 degree C
(If we fix the three sig figs then it could be written as 102 degree C.)
Answer:
a) 40,75 atm
b) 30,11 atm
Explanation:
The Ideal Gas Equation is an equation that describes the behavior of the ideal gases:
PV = nRT
where:
- P = pressure [atm]
- V = volume [L]
- n = number of mole of gas [n]
- R= gas constant = 0,08205 [atm.L/mol.°K]
- T=absolute temperature [°K]
<em>Note: We can express this values with other units, but we must ensure that the units used are the same as those used in the gas constant.</em>
The truncated virial equation of state, is an equation used to model the behavior of real gases. In this, unlike the ideal gas equation, other parameters of the gases are considered as the <u>intermolecular forces</u> and the <u>space occupied</u> by the gas
where:
- v is the molar volume [L/mol]
- B is the second virial coefficient [L/mol]
- P the pressure [atm]
- R the gas constant = 0,08205 [atm.L/mol.°K]
a) Ideal gas equation:
We convert our data to the adecuate units:
n = 5 moles
V = 3 dm3 = 3 L
T = 25°C = 298°K
We clear pressure of the idea gas equation and replace the data:
PV = nRT ..... P = nRT/V = 5 * 0,08205 * 298/3 =40,75 atm
b) Truncated virial equation:
We convert our data to the adecuate units:
n = 5 moles
V = 3 dm3 = 3 L
T = 25°C = 298°K
B = -156,7*10^-6 m3/mol = -156,7*10^-3 L/mol
We clear pressure of the idea gas equation and replace the data:
and v = 3 L/5 moles = 0,6 L/mol