Question

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution

Answer 1

Answer:

16 Molarity

Step-by-step:

M= mols/L

M= 8mols/.5L

M= 16 Molarity

Answer 2

Answer:

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

$Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}$

Moles of NaOH = 8 moles

Volume of the solution = 0.5 L

$Molarity=\frac{8 mol}{0.5 L}=16.0 M$

The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.