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2 years ago

15

A plasma wave moving through a plasma has a frequency of 109 Hz and a speed of 3.0 × 107 m/s. What is the wavelength of this wav

e?

1 answer:

tigry1 [53]2 years ago

8 0

Answer:0.27*10^{6} (m)

Explanation:

with a wave we know that speed= wavelenght* frecuency so

wavelenght= 3*10^{7} / 109 = 0.27*10^{6} (m)

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the magnitude of the magnetic field at point p for a certain electromagnetic wave is 2.21. What is the magnitude of the elctic f

vesna_86 [32]

Answer:

$6.63\times 10^8\ N/C$

Explanation:

Given that,

The magnitude of magnetic field, B = 2.21

We need to find the magnitude of the electric field. Let it is E. So,

$\dfrac{E}{B}=c\\\\E=Bc$

Put all the values,

$E=2.21\times 3\times 10^8\\\\=6.63\times 10^8\ N/C$

So, the magnitude of the electric field is equal to $6.63\times 10^8\ N/C$ .

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2 years ago

One of the harmonics of a string fixed at both ends has a frequency of 52.2 Hz and the next higher harmonic has a frequency of 6

Angelina_Jolie [31]

Solution :

Frequency may be defined as the number of observation or number of waves that is taken in per unit time. The unit of frequency is Hertz or Hz.

It is given that :

Successive harmonic frequencies, f = 52.2 Hz

and f' = 60.9 Hz

Therefore, fundamental frequency, F = f' - f

F = 60.9 - 52.2

F = 8.7 Hz

Therefore the string which is fixed at both the ends forms all the harmonics.

6 0

2 years ago

in an isolated system, two cars, each with a mass of 1,500 kg, collide. car 1 is initially at rest while car 2 is moving at 5 m/

kirza4 [7]

Answer:2.5 m/s

Explanation:

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2 years ago

Jessica decides not to skip school because she does not want to lose her senior privileges if caught. Jessica is at what level o

Elena L [17]

This one is also using pre-conventional moral reasoning.

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3 years ago

A weather balloon is Floating at a constant height above Earth when it releases a pack hot instruments. If the pack hits the gro

Slav-nsk [51]

Answer:

The pack has fallen 275.6 m

Explanation:

The pack is in free fall, so it is moving by uniform accelerated motion, so we can use the following suvat equation:

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where, choosing upward as positive direction:

v is the final velocity

u is the initial velocity

$a=g=-9.8 m/s^2$ is the acceleration of gravity

s is the vertical displacement

For the pack in this problem,

u = 0

v = -73.5 m/s

Solving for s, we find how far the packet has fallen:

$s=\frac{v^2-u^2}{2a}=\frac{(-73.5)^2-0^2}{2(-9.8)}=-275.6 m$

And the negative sign means the direction of the displacement is downward.

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3 years ago