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2 years ago

15

A plasma wave moving through a plasma has a frequency of 109 Hz and a speed of 3.0 × 107 m/s. What is the wavelength of this wav

e?

1 answer:

tigry1 [53]2 years ago

8 0

Answer:0.27*10^{6} (m)

Explanation:

with a wave we know that speed= wavelenght* frecuency so

wavelenght= 3*10^{7} / 109 = 0.27*10^{6} (m)

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The Tesla Roadster electric car is rated at 16.8kW. How much energy does it use during a one hour drive? Answer in MJ

ASHA 777 [7]

(16.8 kW) means (16,800 joules/second)

Energy in 1 hour = (1 hour) x (16,800 J/s) x (3,600 s/hour)

Energy = (16,800 x 3,600) J

Energy = 60,480,000 Joules

Energy = 60.48 MJ

6 0

2 years ago

Read 2 more answers

A 20.0 μf capacitor is charged to a potential difference of 850 v. the terminals of the charged capacitor are then connected to

liberstina [14]

(a) $Q = 1.70\times 10^{-2}\;\text{C}$ ;
(b) $V_\text{final} = 5.31\times 10^{2}\;\text{V}$ ;
(c) $E_\text{final} = 4.52\;\text{J}$ ;
(d) $\Delta E = 2.82\;\text{J}$ .

All four values are in 3 sig. fig.

<h3>Explanation</h3>

(a)

$Q = C\cdot V = 20.0\times 10^{-6} \times 850\;\text{V} = 1.70\times 10^{-2}\;\text{J}$ .

(b)

Sum of the final charge on the two capacitors should be the same as the sum of the initial charge. Voltage of the two capacitors should be the same. That is:

$C_1\cdot V_\text{final} +C_2 \cdot V_\text{final} = C_1\cdot V_\text{initial}$ ;

$(C_1+C_2)\cdot V_\text{final} = C_1\cdot V_\text{initial}$ ;

$\displaystyle V_\text{final} = \frac{C_1}{C_1+C_2}\cdot V_\text{initial}\\\phantom{V_\text{final}} = \frac{20.0\;\mu\text{F}}{20.0\;\mu\text{F} + 12.0\;\mu\text{F}} \times 850\;\text{V}\\\phantom{V_\text{final}} =531\;\text{V}$ .

(c)

$\displaystyle E = \frac{1}{2}\cdot C\cdot V^{2}$ .

$\displaystyle E_\text{final} = \frac{1}{2} (C_1 + C_2) \cdot {V_\text{final}}^{2} \\\phantom{E_\text{final}} = \frac{1}{2} \times (20.0\times 10^{-6} + 12.0\times 10^{-6}) \times 531.25\\\phantom{E_\text{final}} = 4.52\;\text{J}$ .

(d)

Initial energy of the system, which is the same as the initial energy in the $20.0\;\mu\text{F}$ capacitor:

$\displaystyle E_\text{initial} = \frac{1}{2} \times 20.0\times 10^{-6} \times 850^{2} = 7.225\;\text{J}$ .

Change in energy:

$\Delta E = 7.225\;\text{J} - 4.516\;\text{J} = 2.70\;\text{J}$ .

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3 years ago

How much time does it take for a spinning baseball with an angular speed of 38 rad/s to rotate through 15 degrees

Nadusha1986 [10]

Answer:

the time of motion of the ball is 6.89 ms.

Explanation:

Given;

angular speed, ω = 38 rad/s

angular distance, θ = 15 degrees

Angular distance in radian;

$\theta = 15^0 \times\frac{2\pi \ rad}{360^0} = 0.2618 \ rad$

Time of motion is calculated as;

$time = \frac{angular \ distance}{angular \ speed} \\\\t= \frac{\theta}{\omega} = \frac{0.2618 \ rad}{38 \ rad/s} \\\\t = 6.89 \ \times 10^{-3} \ s\\\\t = 6.89 \ ms$

Therefore, the time of motion of the ball is 6.89 ms.

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2 years ago

How much time passes when an object travels at a constant speed of 17 m/s over a distance of 323 m? Identify Variables, write fo

k0ka [10]

Answer: 19 s

Explanation:

The relationship between speed, distance and time is given by:

velocity= distance/time

time= distance/velocity= 323 m/17 m/s= 19 s

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3 years ago

What is the relationship between work and power

Mashcka [7]

Power is the rate work is usually done in.

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2 years ago

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