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2 years ago

6

Which of the following correctly arranges the planets by the size of their diameter in increasing order?

1 answer:

Oksanka [162]2 years ago

6 0

Answer:

Mercury<Venus<Earth<Mars<Jupiter< Saturn< Uranus<Neptune

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If the Sun were to stop shining, Earth would stop receiving heat and light within about eight minutes. Earth, however, would rem

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If<span> The </span>Sun<span> Went Out, How Long </span>Could<span> Life On </span>Earth<span> Survive? ... (which is actually physically impossible), the </span>Earth would stay<span> warm—at least ... from the planet's core </span>would<span> equal the</span>heat<span> that the </span>Earth<span> radiates into space, ... Photosynthesis </span>would<span> halt immediately, and </span>most<span> plants</span>would<span> die </span>in<span> a few </span>weeks<span>.</span>

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3 years ago

Read 2 more answers

As a capacitor is being charged in an RC circuit. the current flowing through a resistor isa) increasingb) decreasingc) constant

Montano1993 [528]

<h2>Answer: decreasing</h2>

An RC circuit is an electrical circuit composed of resistors and capacitors, where the charging time $T$ of the circuit is proportional to the magnitude of the electrical resistance $R$ and the capacity $C$ of the capacitor.

As shown below:

$T=R.C$

In this context, the electrical resistance is the opposition to the flow of electrons when moving through a conductor.

Therefore:

<h2>When a capacitor is being charged in an RC circuit, the current flowing through a resistor <u>decreases</u>.</h2>

And the correct option is b.

4 0

3 years ago

The speed of sound in air is 10 times faster than the speed of a wave on a certain string. The density of the string is 0.002kg/

nata0808 [166]

Answer:

The tension on the string is 2.353 N.

Explanation:

Given;

the speed of sound in air, v₀ = 343 m/s

then, the speed of sound on the string, v = 343 / 10 = 34.3 m/s

mass per unit length, m/l = μ = 0.002 kg/m

The speed of sound on the string is given as;

$v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu$

where;

T is the tension on the string

T = (34.3)²(0.002)

T = 2.353 N

Therefore, the tension on the string is 2.353 N.

3 0

3 years ago

A bicyclist accelerates at 0.89 m/s2 during a 5.0 s interval. What is the change in speed if the bicyclist and the bicycle?

Allisa [31]

Answer:

attached below

Explanation:

3 0

3 years ago

A particle moving along the x-axis has its velocity described by the function vx =2t2m/s, where t is in s. Its initial position

Illusion [34]

Answer:

Follows are the solution to this question:

Explanation:

In point a:

Place of particles

$X(t)=\int V_{x}(t)dt$

$=\int 2t^{2}dt\\\\=\frac{2}{3}t^{3}+C$

$\to t=0\\\\ \to X(0)=2.3 \ m$

$\to X(0)=0+C\\\\ \to C=2.3\ m$

$\to X(t)=( \frac{2}{3})t^3 + 2.3\\\\ \to t=2.2\\\\\to X=( \frac{2}{3})\times 2.2^3 +2.3 \\\\$

$= \frac{2}{3}\times 10.648 +2.3\\\\= \frac{21.296}{3}+2.3\\\\ = 7.09+2.3\\\\ =9.39\\\\ =9.4\ m$

In point b:

when $t=2.2 \ s$

the Particle velocity $(V)=2 \times 2.22 =9.68\ \frac{m}{s}$

In point c:

Calculating the Particle acceleration:

$\to a=\frac{dV}{dt} =4\ t\\\\\to t=2.2 \ s\\\\\to a=4\times 2.2 =8.8 \ \frac{m}{s^2}$

8 0

3 years ago