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9966 [12]
1 year ago
6

Which of the following correctly arranges the planets by the size of their diameter in increasing order?

Physics
1 answer:
Oksanka [162]1 year ago
6 0

Answer:

Mercury<Venus<Earth<Mars<Jupiter< Saturn< Uranus<Neptune

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Consider the numbers 23.68 and 4.12. The sum of these numbers has ____ significant figures, and the product of these numbers has
damaskus [11]

Answer:multiplying will give us 7 significant figures and addition will give us 3 significant figures

Explanation:

After multiplying the two numbers they resulting value will give a value in its 4 decimal places because both given values are in 2 decimal places. The 4 dp is gotten by the addition of the decimal places of both given numbers (2+2) and

The result of its addition will give us a value in its 1dp and 3 significant figures since the addition of 23.68 and 4.12 will give us 27.8

7 0
3 years ago
How many ohms of resistance must be present in a circuit that has 240 volts and a current of 15 amps?
PIT_PIT [208]

Answer:

16 ohms

Explanation:

V= I ⋅ R

where,  V  is the net potential difference in the circuit,  I  is the current in the circuit and  R  is the net resistance of the circuit.  

In this case,  V = 240  volts,  I = 15  amperes.

240 = 15 ⋅ R  

⇒ R = 240/ 15 = 16  ohms

5 0
3 years ago
Read 2 more answers
The diagram shows the top view of a 65-kg student at point A on an amusement park ride. The ride spins the student in a horizont
Elza [17]

Answer:

1923 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 65 Kg

Radius (r) = 2.5 m

Velocity (v) = 8.6 m/s

Centripetal force (F) =?

The centripetal force, F, can be obtained by using the following formula:

F = mv²/r

F = 65 × 8.6² / 2.5

F = 65 × 73.96 / 2.5

F = 4807.4 / 2.5

F = 1922.96 ≈ 1923 N

Thus, the magnitude of the centripetal's force acting on the student is approximately 1923 N

3 0
3 years ago
A windmill converts the mechanical energy of wind into ?
sammy [17]
Electric power most likely. It can be a generator for a power plant if needed. Hope this helped. Sorry if it didn't.
7 0
2 years ago
What are (a) the charge and (b) the charge density on the surface of a conducting sphere of radius 0.20 m whose potential is 240
Lady bird [3.3K]

Answer:

(a) charge q=5.33 nC

(b) charge density σ=10.62 nC/m²

Explanation:

Given data

radius r=0.20 m

potential V=240 V

coulombs constant k=9×10⁹Nm²/C²

To find

(a) charge q

(b) charge density σ

Solution

For (a) charge q

As

V_{potential}=kq/r\\ q=rV_{potential}/k\\q=\frac{(0.20)(240)}{9*10^{9} }\\ q=5.333*10^{-9}C\\or\\ q=5.33nC

For (b) charge density

As charge density σ is given as:

σ=q/(4πR²)

σ=(5.333×10⁻⁹) / (4π×(0.20)²)

σ=10.62 nC/m²

3 0
3 years ago
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