<span>y(x,t)= 2.30mmcos[(6.98rad/m)x + (742 rad/s)t]
</span>A) Amplitude is 2.30mm<span>
B) Frequency 1/</span>2.30mm<span>
C) Wavelength is </span>6.98rad/m<span>
D) Wave Speed is </span>742 rad/s<span>
E) Direction the wave is traveling
</span>
Answer:
The answer is: Pressure increases linearly with the depth
Explanation:
In this case, the definition of pressure is:

where F = mg is the weight of the fluid over the body, and A is the area of the surface to which the force is exerted. If we consider
, then
.
Volume can be expressed as V = A*h, where A is the cross section of the column of the fluid over the body and h is the height of the column, in other words, the depth.
So
,
which means that pressure increases linearly with the depth in a factor of
.
Answer:
Energy is carried by the electric and magnetic fields
Explanation:
Electromagnetic waves consist of electric fields and magnetic fields which oscillate perpendicularly to the direction of propagation of the waves (for this reason, they are called transverse waves).
Electric fields and magnetic fields both possess energy, and this energy is carried through space by the wave. Note that electromagnetic waves do not carry matter, but only energy (in fact, they do not have mass). Moreover, electromagnetic waves are the only type of waves that do not need a medium to propagate: in fact, they can also travel through a vacuum.
Answer:
Slope is calculated using the equation: slope= rise/run (y/x). Take take y value of a point and put it over the x value of the same point and then simplify the fraction.
Explanation:
The maximum allowable torque must correspond to the allowable shear stress for maximization. To solve this, we use the torsion formula:
Max. Allowable Shear Stress = Maximum Torque ÷ Cross-Sectional Area
8 x 10^6 Pa = Maximum Torque ÷ pi*(d/2)²
Maximum Torque = 8 x 10^6 Pa * pi*(0.06/2)² m²
Maximum Torque = 22,619.47 J or
Maximum Torque = 22.62 kJ
As for the second question, I have no reference figure so I am unable to answer it. I hope I was still able to help you, though.