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a_sh-v [17]
3 years ago
7

A. Community B. Organism C. Population D. Individual

Physics
2 answers:
coldgirl [10]3 years ago
6 0

Answer:

B

Explanation:

the answer is Organism

dimulka [17.4K]3 years ago
3 0

Answer:

i think its B or D

Explanation:

its Individual or Organism

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Determining the pH of substances such as purple grape juice and catsup using test strips can be difficult. Why?
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Answer:

Because they would naturally dye the test strips in the colors violet and red, regardless of their pH values

(would really appreciate the brainliest)

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A piece of metal will feel colder than a piece of wood at the same temperature. Why?
alexira [117]
Metals in general, are good heat conductors 
7 0
3 years ago
PLEASE HELP ASAP!!
Stells [14]

Its B: reduce the amount of energy needed to do the work by putting the work onto something else

3 0
3 years ago
Read 2 more answers
A student, who weighs 720N, is standing on a bathroom scale and riding an elevator that is moving downwards with a speed that is
jasenka [17]

Answer:

1) The mass of the student is approximately 73.39 kg

2) The net force on the student is approximately 947.523 N

3) The value the scale will read is approximately 96.59 kg

Explanation:

The given parameters are;

The weight of the student = 720 N

The speed at which the elevator is decreasing = 3.1 m/s²

1) The weight of the student = The mass of the student × The acceleration due to gravity

The acceleration due to gravity is a constant = 9.81 m/s²

Substituting the known values gives;

720 N = The mass of the student × 9.81 m/s²

∴ The mass of the student = 720 N/(9.81 m/s²) ≈ 73.39 kg

2) The forces acting on the student are;

i) The force of gravity which is the weight of the student acting downwards

ii) The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student

The net force, F_{net} = The weight of the student + The inertia force of the slowing elevator

∴ The net force, F_{net} = 720 N + 73.39 kg × 3.1 m/s² ≈ 947.523 N

3) The scale will read the mass of the student as follows;

Mass reading of student on the scale = Force on scale/9.81

∴ Mass reading of student on the scale = 947.523/9.81 ≈ 96.59 kg

The value the scale will read = 96.59 kg.

3 0
3 years ago
Pls help will give brainliest
max2010maxim [7]

Explanation:

the correct answer is Option 5.√½gh.

hope this helps you.

5 0
3 years ago
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