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Pavel [41]
3 years ago
12

In a pneumatic lift, compressed air exerts a force on a piston with a radius of 10.00 cm. This pressure is transmitted to a seco

nd piston with a radius of 25.0 cm. This second piston lifts a crate. Ignoring the weight of the pistons, how large a force must the compressed air exert to lift a crate that is 66.5 N?
Physics
1 answer:
vitfil [10]3 years ago
7 0

Answer:

F₁ = 10.64 N

Explanation:

The pressure is transmitted equally from the first piston to the second piston:

P_1=P_2\\\\\frac{F_1}{A_1}=\frac{F_2}{A_2}\\\\\frac{F_1}{\pi r_1^2}=\frac{F_2}{\pi r_2^2}\\\\\frac{F_1}{r_1^2}=\frac{F_2}{r_2^2}\\\\F_1 = (\frac{F_2}{r_2^2})(r_1^2)

where,

F₁ = Force applied by compressed air on first piston = ?

F₂ = Weight lifted by second piston = 66.5 N

r₁ = radius of first piston = 10 cm

r₂ = radius of second piston = 25 cm

Therefore,

F_1 = \frac{66.5\ N}{(25\ cm)^2} (10\ cm)^2\\\\

<u>F₁ = 10.64 N</u>

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A torque of 36.5 N · m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result
vivado [14]

Answer:

21.6\ \text{kg m}^2

3.672\ \text{Nm}

54.66\ \text{revolutions}

Explanation:

\tau = Torque = 36.5 Nm

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 10.3 rad/s

t = Time = 6.1 s

I = Moment of inertia

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_1 t\\\Rightarrow \alpha_1=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha_1=\dfrac{10.3-0}{6.1}\\\Rightarrow \alpha_1=1.69\ \text{rad/s}^2

Torque is given by

\tau=I\alpha_1\\\Rightarrow I=\dfrac{\tau}{\alpha_1}\\\Rightarrow I=\dfrac{36.5}{1.69}\\\Rightarrow I=21.6\ \text{kg m}^2

The wheel's moment of inertia is 21.6\ \text{kg m}^2

t = 60.6 s

\omega_i = 10.3 rad/s

\omega_f = 0

\alpha_2=\dfrac{0-10.3}{60.6}\\\Rightarrow \alpha_1=-0.17\ \text{rad/s}^2

Frictional torque is given by

\tau_f=I\alpha_2\\\Rightarrow \tau_f=21.6\times -0.17\\\Rightarrow \tau=-3.672\ \text{Nm}

The magnitude of the torque caused by friction is 3.672\ \text{Nm}

Speeding up

\theta_1=0\times t+\dfrac{1}{2}\times 1.69\times 6.1^2\\\Rightarrow \theta_1=31.44\ \text{rad}

Slowing down

\theta_2=10.3\times 60.6+\dfrac{1}{2}\times (-0.17)\times 60.6^2\\\Rightarrow \theta_2=312.03\ \text{rad}

Total number of revolutions

\theta=\theta_1+\theta_2\\\Rightarrow \theta=31.44+312.03=343.47\ \text{rad}

\dfrac{343.47}{2\pi}=54.66\ \text{revolutions}

The total number of revolutions the wheel goes through is 54.66\ \text{revolutions}.

3 0
3 years ago
A projectile is fired vertically upwards and reaches a height of 78.4 m. Find the velocity of projection and the time it takes t
Musya8 [376]

Answer:

1.) U = 39.2 m/s

2.) t = 4s

Explanation: Given that the

height H = 78.4m

The projectile is fired vertically upwards under the acceleration due to gravity g = 9.8 m/s^2

Let's assume that the maximum height = 78.4m. And at maximum height, final velocity V = 0

Velocity of projections can be achieved by using the formula

V^2 = U^2 - 2gH

g will be negative as the object is moving against the gravity

0 = U^2 - 2 × 9.8 × 78.4

U^2 = 1536.64

U = sqrt( 1536.64 )

U = 39.2 m/s

The time it takes to reach its highest point can be calculated by using the formula;

V = U - gt

Where V = 0

Substitute U and t into the formula

0 = 39.2 - 9.8 × t

9.8t = 39.2

t = 39.2/9.8

t = 4 seconds.

7 0
4 years ago
Is it using energy when someone stands against a locker that doesn’t move
soldi70 [24.7K]

When someone stands against a locker and is does not moving at all, then there will be no displacement and since displacement = 0

Work done also becomes equal to zero.

Work done is usually defined as change in energy. Since the work done is zero there has been no energy used.

5 0
3 years ago
Which other element is most likely to be a nonreactive gas?
krok68 [10]

Answer:

A. Argon

Explanation:

It is a noble gas, a group which is not reactive.

5 0
3 years ago
If a light wave is reflected with a 27° angle of reflection, what was the angle of incidence of which it was transmitted?
Leni [432]

Answer:

it is 27 degree.

Explanation:

because angle of reflection is equal to angle of Inc dence

8 0
3 years ago
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