All categories

3 years ago

15 g de nitrato de amonio, NH4NO3 se disuelven en 135 g de agua. La densidad de la

Chemistry

1 answer:

MrRa [10]3 years ago

7 0

Answer:

δ sln = 0.111 g/mL

Explanation:

density (δ): mass/volume

⇒ δ ≡ g solute/mL H2O

∴ m NH4NO3 = 15g

∴ δH2O ≅ 1 g/mL

∴ V H2O = (135g H2O).( mL/1gH2O) = 135 mL H2O

⇒ δ sln = 15 g NH4NO3 / 135 mL H2O = 0.111 g/mL

You might be interested in

Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional

vfiekz [6]

Holes in volcanic rocks illustrates a low pressure and rapid cooling environment(surface of the earth).

Explanation:

Holes in rocks are usually found in a special type of volcanic rock called pumice. The holes signifies a melt that has a lot of dissolved gases in them and they solidify rapid under surface temperature.

Pockets of holes found in some rocks are as a result of trapped gases in cavities of a solidifying magma.
The magma must erupt explosively so that the gases will not have enough time to escape.
During an extrusive magma activity, the low pressure allows for dissolved gases to collects in cavities and magma cools rapidly around them due to the low surface temperature.
The cavities left behind when the gases escape is the hole formed in volcanic rocks.

Learn more:

volcanic eruptions brainly.com/question/1820994

lava volcanic dome brainly.com/question/12426233

#learnwithBrainly

4 0

3 years ago

Convert 0.37 kilograms to grams.

finlep [7]

0.37 kilogramme is the same as 370 grams

5 0

3 years ago

Read 2 more answers

How many grams are in 1.2 moles of neon

DerKrebs [107]

1.2mole•20.17g/1mole= 24.20g

7 0

2 years ago

How many moles are in 17.2g k2s

Natalija [7]

Answer: 0.156 mol

Explanation:

To find the moles of 17.2 g K₂S, we need to know the molar mass to convert.

$17.2g*\frac{mol}{110.256 g} =0.156 mol$

3 0

3 years ago

How many kilojoules of energy would be required to heat a 225g block of aluminum from 23.0 C to 73.5 C?

gulaghasi [49]

Answer:

$\boxed {\boxed {\sf 10.2 \ kJ}}$

Explanation:

We are asked to find how many kilojoules of energy would be required to heat a block of aluminum.

We will use the following formula to calculate heat energy.

$q=mc \Delta T$

The mass (m) of the aluminum block is 225 grams and the specific heat (c) is 0.897 Joules per gram degree Celsius. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.

ΔT = final temperature - inital temperature

The aluminum block was heated from 23.0 °C to 73.5 °C.

ΔT= 73.5 °C - 23.0 °C = 50.5 °C

Now we know all three variables and can substitute them into the formula.

m= 225 g
c= 0.897 J/g° C
ΔT= 50.5 °C

$q= (225 \ g )(0.897 \ J/g \textdegree C)(50.5 \textdegree C)$

Multiply the first two numbers. The units of grams cancel.

$q= (225 \ g * 0.897 \ J/g \textdegree C)(50.5 \textdegree C)$

$q= (225 * 0.897 \ J / \textdegree C)(50.5 \textdegree C)$

$q= (201.825\ J / \textdegree C)(50.5 \textdegree C)$

Multiply again. This time, the units of degrees Celsius cancel.

$q= 201.825 \ J * 50.5$

$q= 10192.1625 \ J$

The answer asks for the energy in kilojoules, so we must convert our answer. Remember that 1 kilojoule contains 1000 joules.

$\frac { 1 \ kJ}{ 1000 \ J}$

Multiply by the answer we found in Joules.

$10192.1625 \ J * \frac{ 1 \ kJ}{ 1000 \ J}$

$10192.1625 * \frac{ 1 \ kJ}{ 1000 }$

$\frac {10192. 1625}{1000} \ kJ$

$10.1921625 \ kJ$

The original values of mass, temperature, and specific heat all have 3 significant figures, so our answer must have the same. For the number we found, that is the tneths place. The 9 in the hundredth place tells us to round the 1 up to a 2.

$10.2 \ kJ$

Approximately <u>10.2 kilojoules</u> of energy would be required.

3 0

3 years ago