In Fraunhofer diffraction wave front used is __________. A. Spherical B. Circular C. Plane D. Conical

The universe was 5 percent its current size when light left objects observed now at redshift of ______________

Nuetrik [128]

The redshift of distant galaxy are larger than those of closer galaxies, which indicates that the galaxy is receding at a faster rate.

The Universe was 5 percent its current size when light left objects now at redshift of 19.

Reasons:

The size of the universe represented as a scale factor with relation to the redshift can be presented as follows;

$\displaystyle \frac{a}{a_0} =\mathbf{ \frac{1}{1 + z}}$

Where;

a₀ = The current size of the Universe

a = The size of the early Universe = 5% of a

Therefore;

$\displaystyle \frac{a}{a_0} =5\% = 0.05= \frac{1}{1 + z}$

$\displaystyle 0.05 = \frac{1}{1 + z}$

0.05 + 0.05·z = 1

$\displaystyle z = \mathbf{ \frac{1 - 0.05}{0.05} } = 19$

The redshift is of the observed light is, z = 19

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4 0

2 years ago

A metal pot feels hot to the touch, but the plastic handle does not. Which type of material is the plastic handle? A. A thermal

gtnhenbr [62]

D is the answer..........

3 0

3 years ago

Read 2 more answers

a 25-N net force is applied to a rolling cart and pruduces an acceleration of 5 m/s 2 what’s the cart mass

nignag [31]

Answer:

The mass of the cart is 5 kg

Explanation:

You divide 25 by 5 and get 5. Have a great day! :D

The Equation:

25/5 = 5

8 0

2 years ago

Solution A has a speciﬁc heat of 2.0 J/g◦C. Solution B has a speciﬁc heat of 3.8 J/g◦C. If equal masses of both solutions start

fgiga [73]

Answer: 2. Solution A attains a higher temperature.

Explanation: Specific heat simply means, that amount of heat which is when supplied to a unit mass of a substance will raise its temperature by 1°C.

In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.

Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.

We have a formula for such condition,

$Q=m.c.\Delta T$ .....................................(1)

where:

$\Delta T$ = temperature difference

Q= heat energy

m= mass of the body

c= specific heat of the body

Proving mathematically:

According to the given conditions

we have equal masses of two solutions A & B, i.e. $m_A=m_B$

equal heat is supplied to both the solutions, i.e. $Q_A=Q_B$

specific heat of solution A, $c_{A}=2.0 J.g^{-1} .\degree C^{-1}$

specific heat of solution B, $c_{B}=3.8 J.g^{-1} .\degree C^{-1}$

$\Delta T_A$ & $\Delta T_B$ are the change in temperatures of the respective solutions.

Now, putting the above values

$Q_A=Q_B$

$m_A.c_A. \Delta T_A=m_B.c_B . \Delta T_B\\\\2.0\times \Delta T_A=3.8 \times \Delta T_B\\\\ \Delta T_A=\frac{3.8}{2.0}\times \Delta T_B\\\\\\\frac{\Delta T_{A}}{\Delta T_{B}} = \frac{3.8}{2.0}>1$

Which proves that solution A attains a higher temperature than solution B.

7 0

3 years ago

Which of these changes will increase the energy loss of a building?

fenix001 [56]

1. The velocity decreases, and the kinetic energy decreases.

2. An increase in temperature difference between the inside and outside of the building.

3. The total kinetic energy remains the same.

4. 76,761 J

5. The energy loss must increase.

6 0

3 years ago