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3 years ago

It is a set of measure designed to determine the level of physical fitness?

Physics

1 answer:

JulsSmile [24]3 years ago

6 0

<em>The PFT or physical fitness test is a set of measures designed to determine the level of physical fitness.....</em>

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Four identical resistors have 12 ohm each. Find the equivalent resistance Req when : (a) all four of them are connected in serie

Elanso [62]

Answer:

(a): When the four resistors are connected in series the equivalent resistor value is Req= 48Ω

(b): when the four resistors are connected in parallel the equivalent resistor value is Req=3Ω

Explanation:

R=R1=R2=R3=R4= 12Ω

(a)

Req= R1+R2+R3+R4

Req= 48 Ω

(b)

Req= (1/12 * 4)⁻¹

Req= 3 Ω

6 0

3 years ago

Please help, I really don't know

zubka84 [21]

circular motion.

cent acc = r omega^2 ... omega is ang vel ... omega=2pi/T ,,,

9.8=rx(2pi/T)^2

if r is known, solve for T

7 0

3 years ago

(II) A 0.72-m-diameter solid sphere can be rotated about an axis through its center by a torque of 10.8 m • N which accelerates

kozerog [31]

Answer:

$m = 23.3 kg$

Explanation:

As we know that it will have constant torque on it

so the acceleration of the ball will be constant so here we can say that we can use kinematics equation

$\theta = \omega_i t + \frac{1}{2}\alpha t^2$

$160(2\pi) = 0 + \frac{1}{2}\alpha (15^2)$

$320 \pi = 112.5 \alpha$

so we have

$\alpha = \frac{320\pi}{112.5}$

$\alpha = 8.94 rad/s^2$

now we know that

$\tau = I \alpha$

$10.8 = I(8.94)$

$I = 1.21 kg m^2$

so we know that

$I = \frac{2}{5}mR^2$

here we know that

diameter = 0.72 m

so radius (R) = 0.36 m

$\frac{2}{5}m(0.36^2) = 1.21$

$m = 23.3 kg$

8 0

3 years ago

What is the gravitational potential energy of the 6 kg cart as it sits the top of the incline?

ella [17]

There are some missing details in the question. Found them on internet:
- the mass of the cart is m=40 kg
- The height of the incline is h=300 m (see attached figure)

Solution:
the gravitational potential energy of an object is given by
$U=mgh$
where
m is the mass of the object
g is the gravitational acceleration
h is the height of the object above the reference point (usually taken as the ground)

By applying this formula, we find the potential energy of the cart at the top of the incline:
$U=mgh=(40 kg)(9.81 m/s^2)(300 m)=1.18 \cdot 10^5 J$