Answer:
The acceleration of the proton is 9.353 x 10⁸ m/s²
Explanation:
Given;
speed of the proton, u = 6.5 m/s
magnetic field strength, B = 1.5 T
The force of the proton is given by;
F = ma = qvB(sin90°)
ma = qvB
where;
m is mass of the proton, = 1.67 x 10⁻²⁷ kg
charge of the proton, q = 1.602 x 10⁻¹⁹ C
The acceleration of the proton is given by;
Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²
Answer:
R=V/I=6/2=3ohm
time =5minutes =5*60=300seconds
I=2A
Heat =I^2Rt=(2)^2*3*300=4*900=3600J
Answer:
0.8726 
Explanation:
We are to convert 1.85 x 
to
First, let us convert the numerator from ft3 to m3
1 ft3 = 0.0283 m3
Hence,
1.85 x ft3 = 1.85 x x 0.0283 m3
= 52.355 m3
Now, let us convert the denominator from minutes to seconds
1 min = 60 sec
Therefore;
1.85 x = 52.355/60
= 0.8726
D.) Distance travelled / time ...........
Answer:
answer a, 4
Explanation:
when the 4 is before the compound it applies to the whole compound
