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jasenka [17]
3 years ago
7

Jane puts some water into an electric kettle and then she connects it to the power source. She observes that after some time the

water inside the kettle heats up and begins to boil. What is happening? A) Light energy is transforming into heat. Eliminate B) Heat energy is transforming into electricity. C) Electrical energy is transforming into heat energy. D) Electrical energy is transforming into light and heat energy.
Physics
2 answers:
Elodia [21]3 years ago
5 0

Answer: The correct answer is option C.

Explanation:

Electrical energy is an energy possessed by the electrical charges in motion.

Heat energy is an energy due to the motion of particles like atoms, ions etc in solid , liquid and gases .

In an electric kettle:

Electric energy → Heat energy   (Law of conservation Energy)

In an electric kettle electric energy is changing into heat energy which results in heating up of water present in side it.The electric energy from the power source is transforming into heat energy which gets transferred to water molecules.

Hence, the correct answer is option C.

Setler [38]3 years ago
4 0
C) electrical energy is transformed into heat energy
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Ball 1, with a mass of 100 g and traveling at 10 m/s, collides head-on with ball 2, which has a mass of 300 g and is initially a
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There is 4000 balls in the earth of the world why is that so hard for you
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2 years ago
Define an astronomical unit. Choose all that apply. a. 8.3 minutes Average distance from Earth to the Sun. b. Distance that ligh
Naddik [55]

Answer:

a. 8.3 minutes average distance from earth to the sun

d. 93 miles or 150 million km

Explanation:

The distance between the earth and the sun is defined as an astronomical unit (AU). It takes 8.3 minutes to go from earth to the sun at the speed of light. That distance has a length of 150 million Kilometers or 93 miles.  

It is common to see in planet charts that distance to the sun are compared in astronomical units. In the case of Mars is 1.524 AU away from the sun.

6 0
3 years ago
Are these two correct ?
gulaghasi [49]

Answer:

7. Your answer is correct dear, just add the unit

8. answer is 1.17m/s²

Explanation:

queation 7.

m = 3kg, F = 9N, a ?

F = ma

a = F/m = 9/3 = 3m/s²

Use the same approach for question 8

5 0
3 years ago
The force exerted by the wind on the sails of a sailboat is Fsail = 330 N north. The water exerts a force of Fkeel = 210 N east.
Elena L [17]

Answer:

The magnitude of the acceleration is a_r = 1.50 \ m/s^2

The direction is  \theta =  32.5 6^o north of  east

Explanation:

From the question we are told that

   The force exerted by the wind is  F_{sail} =  (330 ) \ N \ north

   The force exerted by water is  F_{keel} =  (210  ) \ N \ east

      The mass of the boat(+ crew) is  m_b  =  260  \ kg

Now Force is mathematically represented as

      F =  ma

Now the acceleration towards the north is mathematically represented as

      a_n  =  \frac{F_{sail}}{m_b}

substituting values

       a_n  =  \frac{330 }{260}

      a_n  =  1.269 \ m/s^2

Now the acceleration towards the east is mathematically represented as

       a_e = \frac{F_{keel}}{m_b }

substituting values

      a_e = \frac{210}{260}

      a_e =0.808 \ m/s^2

The resultant acceleration is  

      a_r =  \sqrt{a_e^2 + a_n^2}

substituting values

     a_r =  \sqrt{(0.808)^2 + (1.269)^2}

      a_r = 1.50 \ m/s^2

The direction with reference from the north is evaluated as

Apply SOHCAHTOA

        tan \theta =  \frac{a_e}{a_n}

       \theta = tan ^{-1} [\frac{a_e}{a_n } ]

substituting values

     \theta = tan ^{-1} [\frac{0.808}{1.269 } ]

    \theta = tan ^{-1} [0.636 ]

   \theta =  32.5 6^o

     

   

       

5 0
4 years ago
Consider the expression below. Assume m is an integer. 6m(2m + 18) Enter an expression in the box that uses the variable m and m
Anika [276]
6x2=12m
6x18=108
12m+108
Simplified: m+9 bc 12/12 and 108/12
8 0
4 years ago
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