Question

PLEASE HELP!!!!! 30 POINTS!!! Expand (2x-3y^2)^3 using pascals triangle

Answer 1

Answer:

$(2x-3y^{2} ) * (2x-3y^{2} ) * (2x-3y^{2} )$

=(1) 2x*2x*2x = 8x^3

(2) -3y^2* -3y^2* -3y^2 = $-27y^{6}$

(3) 2x * -3y^2 * 2x = -12 x^2 y^2

(4)-3y^2*-3y^2*2x = 18xy^4

(5)  -3y^2*-3y^2*2x = 18xy^4

(6) 3y^2*-3y^2*2x = 18xy^4

(7)  2x * -3y^2 * 2x = -12 x^2 y^2

(8)2x * -3y^2 * 2x = -12 x^2 y^2

final answer: $8x^3 -36x^2y^2+54xy^4-27y^6$