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3 years ago

PLEASE HELP!!!!! 30 POINTS!!! Expand (2x-3y^2)^3 using pascals triangle

Mathematics

1 answer:

WINSTONCH [101]3 years ago

8 0

Answer:

$(2x-3y^{2} ) * (2x-3y^{2} ) * (2x-3y^{2} )$

=(1) 2x*2x*2x = 8x^3

(2) -3y^2* -3y^2* -3y^2 = $-27y^{6}$

(3) 2x * -3y^2 * 2x = -12 x^2 y^2

(4)-3y^2*-3y^2*2x = 18xy^4

(5) -3y^2*-3y^2*2x = 18xy^4

(6) 3y^2*-3y^2*2x = 18xy^4

(7) 2x * -3y^2 * 2x = -12 x^2 y^2

(8)2x * -3y^2 * 2x = -12 x^2 y^2

final answer: $8x^3 -36x^2y^2+54xy^4-27y^6$

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(2x - 3y)(4x - y) Please help

andre [41]

(2x - 3y) (4x - y) = 8x² - 2xy - 12xy + 3y²

(2x - 3y) (4x - y) = 8x² -14xy + 3y²

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Answer:8x² -14xy + 3y²
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3 0

3 years ago

A carnival is selling ride tickets 5 for $6, 10 for $12, or 15 for $18. What is

maw [93]

Answer:

one ticket is $1.20

Step-by-step explanation:

6 / 5 = 1.2, then check it by multiplying 1.2 x 5. Its easier than you think. Im positive im correct. All you have to do is one but if u want to make sure you can do all of them

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=4%20%20%20%7B%7D%5E%7Bx%20%7D%20%20%2B%206%20%7B%7D%5E%7Bx%7D%20%3D%209%20%7B%7D%5E%7Bx%7D%20%

Nookie1986 [14]

So, the value of x is 1.19

The question is an exponential equation

<h3>What is an exponential equation?</h3>

An exponential equation is a mathematical expression between two quantities in which one variable is raised to a power of the other variable.

Since $4^{x} + 6^{x} = 9^{x}$ ,

Dividing through by 4ˣ, we have

$\frac{4^{x} }{4^{x} } + \frac{6^{x} }{4^{x} } = \frac{9^{x} }{4^{x} } \\1 + (\frac{6}{4})^{x} } = (\frac{9}{4})^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3^{2} }{2^{2} })^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3}{2})^{2x} }$

Let y = (3/2)ˣ

So,

1 + y = y²

y² - y - 1 = 0

Using the quadratic formula to find y,

$y = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

where a = 1 b = -1 and c = -1

Substituting the values of the variables into the equation, we have

$y = \frac{-(-1) +/- \sqrt{(-1)^{2} - 4\times 1 \times (-1)} }{2\times 1}\\= \frac{1 +/- \sqrt{1 + 4} }{2}\\= \frac{1 +/- \sqrt{5} }{2}\\= \frac{1 - \sqrt{5} }{2} or \frac{1 + \sqrt{5} }{2}\\= \frac{1 - 2.236}{2} or \frac{1 + 2.236}{2}\\= \frac{- 1.236}{2} or \frac{3.236}{2}\\= -0.618 or 1.618$