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cestrela7 [59]
2 years ago
11

Help me guysClass IX​

Physics
1 answer:
goldfiish [28.3K]2 years ago
4 0

Answer:

with right hand grip rule

3. A- south

B- north

C- north

D- south

E- south

F- north

sorry idk what 1st & 2nd question means

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A client with hypertension who weighs 72.4 kg is receiving an infusion of nitroprusside (Nipride) 50 mg in D5W 250 ml at 75 ml/h
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To solve this problem it is necessary to simply apply the concepts related to cross-multiply and proportion between units.

Let's start first by relating the amount of dose needed to be supplied per hour, in other words,

The infusion of 250ml should be supplied at a rate of 75ml / hour, so what amount x of mg hour should be supplied with 50Mg.

\frac{x}{75ml/hour} \rightarrow \frac{50mg}{250ml}

x \rightarrow \frac{50mg*75ml/hour}{250ml}

x \rightarrow \frac{3750mg}{250hour}

x \rightarrow 15\frac{mg}{hour}

Converting to mcg units we know that 1mg is equal to 1000mcg and that 1 hour contains 60 min, therefore

x \rightarrow 15\frac{mg}{hour}

x \rightarrow 15\frac{mg}{hour}(\frac{1000mcg}{1mg})(\frac{1hour}{60min})

x \rightarrow 250mcg/min

The dose should be distributed per kilogram of the patient so if the patient weighs 72.4kg,

Dose = \frac{250mcg/min}{72.4kg}

Dose = 3.5 \frac{mcg/min}{kg}

Therefore the client will receive 3.5mcg/kg/min.

8 0
3 years ago
State the law of universal gravitation, and use examples to explain how changes in mass and changes in distance affect gravitati
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What is the definition of energy ​
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5 0
3 years ago
What is the force in N of an object that has a mass of 7 kilograms and an acceleration of 4 m/s/s
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Newton's 2nd law of motion:         Force = (mass) x (acceleration)

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3 years ago
A group of college students eager to get to Florida on a spring break drove the 710-mi trip with only minimum stops. They comput
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Answer:

Time taken for trip = 12.74 hour (Approx)

Explanation:

Given:

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Average speed for the trip = 55.7 mi/h

Find:

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⇒ Time = Distance / Speed

⇒ Time taken for trip = Distance of trip / Average speed for the trip

⇒ Time taken for trip = 710-mi / 55.7 mi/h

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