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3 years ago

14

A person pushes a 50kg box to the right with 100N of force at a constant velocity of 5m/s. Calculate the coefficient of friction

between the box and the surface.

1 answer:

Anna11 [10]3 years ago

8 0

The weight of the box is 50x9.8 = 490 N. The force of friction is 100N. F= μΝ so coefficient = 100/490 = 0.20

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Answer:

Explanation:

Given:

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g = w^2R

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= 4.905 m/s^2

In conclusion,

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g2 = (g1 × 65)/130

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Explanation:

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