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melamori03 [73]
3 years ago
9

A chain has a mass of 10.0 kg. It is hanging freely, at rest, with one end connected to a ceiling hook.

Physics
1 answer:
Elza [17]3 years ago
8 0

Answer:

Identify the object to be analyzed. For some systems in equilibrium, it may be necessary to consider more than one object. Identify all forces acting on the object. Identify the questions you need to answer. Identify the information given in the problem. In realistic problems, some key information may be implicit in the situation rather than provided explicitly.

Explanation:

Identify the object to be analyzed. For some systems in equilibrium, it may be necessary to consider more than one object. Identify all forces acting on the object. Identify the questions you need to answer. Identify the information given in the problem. In realistic problems, some key information may be implicit in the situation rather than provided explicitly.

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1. A particle is projected vertically upwards with a velocity of 30 ms from a point 0. Find (a) the maximum height reached(b) th
Bogdan [553]

Assuming the particle is in free fall once it is shot up, its vertical velocity <em>v</em> at time <em>t</em> is

<em>v</em> = 30 m/s - <em>g t</em>

where <em>g</em> = 9.8 m/s² is the magnitude of the acceleration due to gravity, and its height <em>y</em> is given by

<em>y</em> = (30 m/s) <em>t</em> - 1/2 <em>g t</em> ²

(a) At its maximum height, the particle has 0 velocity, which occurs for

0 = 30 m/s - <em>g t</em>

<em>t</em> = (30 m/s) / <em>g</em> ≈ 3.06 s

at which point the particle's maximum height would be

<em>y</em> = (30 m/s) (3.06 s) - 1/2 <em>g</em> (3.06 s)² ≈ 45.9184 m ≈ 46 m

(b) It takes twice the time found in part (a) to return to 0 height, <em>t</em> ≈ 6.1 s.

(c) The particle falls 35 m below its starting point when

-35 m = (30 m/s) <em>t</em> - 1/2 <em>g t</em> ²

Solve for <em>t</em> to get a time of about <em>t</em> ≈ 7.1 s

7 0
3 years ago
A student decides to spend spring break by driving 50 miles due east, then 50 miles 30 degrees south of east, then 50 miles 30 d
PolarNik [594]

Answer:

a. 600 ml, 12

Explanation:

The movement described in the question exhibits that of a polygon. Exhibiting a constant distance and angle with only varying direction until the starting point is reached.

The sum of exterior angles of a polygon = 360 degrees.

Exterior angle of a polygon = (360 ÷ number of sides)

Therefore,

Number of sides = 360 ÷ exterior angle

Exterior angle = 30 degrees

Hence,

Number of sides = 360 ÷ 30 = 12 sides

Since distance traveled of 50 miles is the same for each displacement ;

Total displacement = distance traveled * number of sides

Total displacement = 50 * 12 = 600 miles.

5 0
3 years ago
A cylindrical rod of mass M. length L and radius R has two cords wound around it whose ends are a
Rudik [331]

Answer:

T = mg/6

Explanation:

Draw a free body diagram (see attached).  There are two tension forces acting upward at the edge of the cylinder, and weight at the center acting downwards.

The center rotates about the point where the cords touch the edge.  Sum the torques about that point:

∑τ = Iα

mgr = (1/2 mr² + mr²) α

mgr = 3/2 mr² α

g = 3/2 r α

α = 2g / (3r)

(Notice that you have to use parallel axis theorem to find the moment of inertia of the cylinder about the point on its edge rather than its center.)

Now, sum of the forces in the y direction:

∑F = ma

2T − mg = m (-a)

2T − mg = -ma

Since a = αr:

2T − mg = -mαr

Substituting expression for α:

2T − mg = -m (2g / (3r)) r

2T − mg = -2/3 mg

2T = 1/3 mg

T = 1/6 mg

The tension in each cord is mg/6.

7 0
3 years ago
Which statement describes nuclear fission
Harlamova29_29 [7]

The Splitting of a nucleus

3 0
3 years ago
Read 2 more answers
One end of a 7-cm-long spring is attached to the ceiling. When a 5.4 kg mass is hung from the other end, the spring is stretched
mash [69]

Answer:

2.63 cm

Explanation:

Hooke's law gives that the force F is equal to cy where c is spring constant and x is extension

Making c the subject of the formula then

c=\frac {F}{y}

Since F is gm but taking the given mass to be F

c=\frac {5.4 kg}{4.3 cm}=1.2558139534883720930232558139534883720930

By substitution now considering F to be 3.3 kg

y=\frac {3.3 kg}{1.2558139534883720930232558139534883720930}=2.6277777777777 cm\approx 2.63 cm

8 0
4 years ago
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