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arlik [135]
4 years ago
15

Three identical metal spheres are on insulating stands. Sphere A is given an initial charge of q. Sphere A is then briefly touch

ed to Sphere B. Afterward, Sphere B is then briefly touched to Sphere C. What amount of charge does each sphere now have?
. A

Sphere A - 0.25 q

Sphere B - 0.5 q

Sphere C - 0.25 q


B.

Sphere A - 0.25 q

Sphere B - 0.5 q

Sphere C - 0.25 q


C.

Sphere A - 0.33 q

Sphere B - 0.33 q

Sphere C - 0.33 q


D.

Sphere A - 0.5 q

Sphere B - 0.25 q

Sphere C .025 q
Physics
1 answer:
REY [17]4 years ago
4 0

Answer:

Hi fernyestrealla How r u

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B.to examine a beam of charged particles

Explanation:

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A powerful searchlight shines on a man. The man's cross-sectional area is 0.500m2 perpendicular to the light beam, and the inten
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Answer:

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N

(b) the force the light beam exerts is much too small to be felt by the man.

Explanation:

Given;

cross-sectional area of the man, A = 0.500m²

intensity of light, I = 35.5kW/m²

If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;

P = I/c

where;

P is the pressure of the incident light

I is the intensity of the incident light

c is the speed of light

P = \frac{I}{c} =\frac{35500}{3*10^8} = 1.18*10^{-4} \ N/m^2

F = PA

where;

F is the force of the incident light on the man

P is the pressure of the incident light on the man

A is the cross-sectional area of the man

F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N

The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N

Therefore, the force the light beam exerts is much too small to be felt by the man.

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4 years ago
Lori wants to send a box of oranges to a friend by mail. The box of oranges cannot exceed a mass of 10.222 Kg. If each orange ha
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Explanation:

Given that,

The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.

The mass of each orange is 198 g

We know that,

1 kg = 1000 g

10.222 kg = 10.222×1000 g

Let there are n number of oranges. So,

n=\dfrac{10.222\times 1000\ g}{198\ g}\\\\n=51.92\approx 52\ \text{oranges}

It means she can send 52 oranges and it is maximum quantity.

4 0
4 years ago
Calculate the heat gained by 100 grams of ice at -20°C in order to become water at 50°C. ( C = .5 for ice and C = 1 for water, Q
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Answer:

6008 cal

Explanation:

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c_{i}  = specific heat of ice = 0.5 cal/(kg°C)

c_{w}  = specific heat of water = 1 cal/(kg°C)

L  = Latent heat of fusion of ice = 80 J/g

T_{i}  = initial temperature of ice = - 20 °C

T_{f}  = final temperature of ice = 50 °C

Q = Heat gained

Heat gained is given as

Q = m_{i} c_{i}(0 - (T_{i}))+ m_{i}L + m_{i}c_{w}(T_{i} - 0)

Q = (100) (0.5) (0 - (- 20))+ (0.1)(80) + (100) (1)(50 - 0)

Q = 6008 cal

8 0
4 years ago
A car with a momentum of 1200 kg.m/s with a mass of 600 kg hit a trash can which was on the side of the road,If the mass of tras
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Speaking that the trash can absorb the momentum. It only should go 5
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