3 years ago

A force of 9.6 N acts on a 5.1 kg object for 8.2 s. Calculate the object's change in velocity (in m/s).

Physics

1 answer:

Alexxandr [17]3 years ago

7 0

Answer:

15.4

Explanation:

F=m×(v, initial-v,terminal )/time

therefore, change of velocity=F×t/m

=9.6×8.2/5.1

=15.4 m/s

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$\underline {\huge \boxed{ \sf \color{skyblue}Answer : }}$

Given :

$\tt \large {\color{purple} ↬ } \: \: \: \: \: I_{D} = 5mA$

$\: \:$

$\tt \large {\color{purple} ↬ } \: \: \: \: \: I_{DSS} = 10mA$

$\: \:$

$\tt \large {\color{purple} ↬ } \: \: \: \: \: V_{GS(off)} = -6V$

$\: \:$

$\tt \large {\color{purple} ↬ } \: \: \: \: \: V_{GS} = {?}$

$\: \: \:$

Let's Slove :

$\tt \large I_{D} = I_{(DSS)} (1 - \frac {V_{GS}}{V_{GS(off)}} )^{2}$

$\: \: \:$

$\tt \large \: V_{GS} = (1 - \frac{ \sqrt{I_D} }{ \sqrt{I_{DSS}} } ) \times V_{GS(off)}$

$\: \: \:$

$\tt \large \: V_{GS} = (1 - \frac{ \sqrt{5m} }{ \sqrt{10m} } ) \times { - 6}$

$\: \:$

$\underline \color{red} {\tt \large \boxed {\tt V_{GS} = 1.75 ✓}}$

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1 year ago

A force of 9.6 N acts on a 5.1 kg object for 8.2 s. Calculate the object's change in velocity (in m/s).​

A force of 9.6 N acts on a 5.1 kg object for 8.2 s. Calculate the object's change in velocity (in m/s).