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3 years ago

A force of 9.6 N acts on a 5.1 kg object for 8.2 s. Calculate the object's change in velocity (in m/s).

Physics

1 answer:

Alexxandr [17]3 years ago

7 0

Answer:

15.4

Explanation:

F=m×(v, initial-v,terminal )/time

therefore, change of velocity=F×t/m

=9.6×8.2/5.1

=15.4 m/s

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When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV1.4=C

DiKsa [7]

Answer:

$\frac{dV}{dt}=21.21cm^3/min$

Explanation:

We are given that

$PV^{1.4}=C$

Where C=Constant

$\frac{dP}{dt}=-7KPa/minute$

V=420 cubic cm and P=99KPa

We have to find the rate at which the volume increasing at this instant.

Differentiate w.r.t t

$V^{1.4}\frac{dP}{dt}+1.4V^{0.4}P\frac{dV}{dt}=0$

Substitute the values

$(420)^{1.4}\times (-7)+1.4(420)^{0.4}(99)\frac{dV}{dt}=0$

$1.4(420)^{0.4}(99)\frac{dV}{dt}=(420)^{1.4}\times (7)$

$\frac{dV}{dt}=\frac{(420)^{1.4}\times (7)}{1.4(420)^{0.4}(99)}$

$\frac{dV}{dt}=21.21cm^3/min$

5 0

3 years ago

Read 2 more answers

A 5.00-a current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. copper has 8.5 * 1028 free ele

vlada-n [284]

The correct answer is: $3.125*10^{19}$ electrons/second

Explanation:

5A current is passing through the copper wire and the light bulb; it means that 5 Coulombs of charge per second is passing through the wire (as current = coulombs/second). To find the electrons per second, the following formula is used:

Electrons per second = $n_e=\frac{5}{e}=\frac{5}{ 1.60\cdot 10^{-19}}=3.125*10^{19}$

7 0

3 years ago

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What’s 3 times 10 to the 8th power divided by 2.45 times 10 to the 9th power

Virty [35]

0.12244898 is the value obtained when solving the given.

<u>Explanation:</u>

Given:

3 times 10 to the 8th power can be expressed in equation format as $3 \times 10^{8}$ (3 times symbolizes ‘multiplication’ then it is to the tenth power of 8)

2.45 times 10 to the 9th power can be expressed in equation format as $2.45 \times 10^{9}$ (2.45 times symbolizes ‘multiplication’, then it is to the tenth power of 9)

Asked to find the solution when dividing the above,

$\frac{3 \times 10^{8}}{2.45 \times 10^{9}}=\frac{3}{2.45} \times 10^{8-9}$

When the tenth power of any value goes from denominator to numerator and vice-versa, presents in opposite sign to that it possess (like when ‘ $10^{9}$ ' goes to numerator changed as ' $10^{-9}$ ').