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AnnZ [28]
3 years ago
8

A force of 9.6 N acts on a 5.1 kg object for 8.2 s. Calculate the object's change in velocity (in m/s).​

Physics
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

15.4

Explanation:

F=m×(v, initial-v,terminal )/time

therefore, change of velocity=F×t/m

=9.6×8.2/5.1

=15.4 m/s

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To solve this problem we will apply the concepts related to Reyleigh's criteria. Here the resolution of the eye is defined as 1.22 times the wavelength over the diameter of the eye. Mathematically this is,

\theta = \frac{1.22 \lambda }{D}

Here,

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Sin\theta = \frac{d}{L}

For small angle, sin\theta = \theta

sin \theta = \frac{d}{L}

Here,

d = Distance between lights

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4 0
3 years ago
A car mass of 1.2 x 10 kilograms starts from rest and attains a speed of 20 meters/seconds in 5 seconds. What net force acted on
lorasvet [3.4K]

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Explanation:

mass of car= 1.2 x 10³ Kg

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Now force is given by F = ma

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7 0
3 years ago
What happens to air pressure as altitude decreases
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Pressure decreases with increasing altitude. The pressure at any level in the atmosphere may be interpreted as the total weight of the air above a unit area at any elevation. At higher elevations, there are fewer air molecules above a given surface than a similar surface at lower levels.
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\epsilon - Ir
this is equal to the voltage drop on the resistance of the motor R:
RI
so we can write:
\epsilon - Ir = RI
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