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2 years ago

According to Newton’s first law of motion what will an object in motion do when no external force acts on it ?

Physics

1 answer:

Alika [10]2 years ago

6 0

it will remain with a uniform rectilinear motion

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Physics question A spacecraft descends vertically near the surface of Planet X. An upward thrust of 25.0kN from its engines slow

Evgesh-ka [11]

F=m*a and m is constant on any planet
25000-m*g=m*1.2
10000-m*g=-m*0.80
m*g is the weight
25000/1.2-m*g/1.2=m
10000/0.80-m*g/0.80=-25000/1.2+m*g/1.2 solve for m*g
m*g=(10000/0.80+25000/1.2)/ (1/1.2+1/0.80)
16 kN

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3 years ago

HELP!! ILL GIVE BRAINLIEST As we've learned so far, the popular model of the solar system shifted over

Mademuasel [1]

Answer:

geotric earth simulator I think ya I have no idea

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3 years ago

The CIA investigated hypnosis as a possible tool for interrogating prisoners. Why did they decide it was unsuitable for that

alukav5142 [94]

Answer:

D. Hypnosis can make the subjects talk, but they talk only about their childhoods.

Explanation:

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3 years ago

Read 2 more answers

A mass m is attached to an ideal massless spring. When this system is set in motion with amplitude a, it has a period t. What is

Luden [163]

The period will be the same if the amplitude of the motion is increased to 2a

What is an Amplitude?

Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Here,

mass m is attached to the spring.

mass attached = m

time period = t

We know that,

The time period for the spring is calculated with the equation:

$T = 2\pi \sqrt{\frac{m}{k} }$

Where k is the spring constant

Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.

From the equation, we can say,

Time period of the spring is independent of the amplitude.

Hence,

Increasing the amplitude does not affect the period of the mass and spring system.

Learn more about time period here:

<u>brainly.com/question/13834772</u>

#SPJ4

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2 years ago

A diffraction pattern forms when light passes through a single slit. The wavelength of the light is 691 nm. Determine the angle

expeople1 [14]

Explanation:

Given that,

Wavelength of the light, $\lambda=691\ nm=691\times 10^{-9}\ m$

(a) Slit width, $a=3.8\times 10^{-4}\ m$

The angle that locates the first dark fringe is given by :

$sin\theta=\dfrac{\lambda}{a}$

$sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-4}}$

$\theta=0.104^{\circ}$

(b) Slit width, $a=3.8\times 10^{-6}\ m$

The angle that locates the first dark fringe is given by :

$sin\theta=\dfrac{\lambda}{a}$

$sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-6}}$

$\theta=10.47^{\circ}$

Hence, this is the required solution.

7 0

3 years ago