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chubhunter [2.5K]
3 years ago
14

The measure of one of the small angles of a right triangle is 45 less than twice the measure of the other small angle. Find the

measure of both angles.
Physics
1 answer:
astra-53 [7]3 years ago
4 0

Answer:

The other two small angles are 45° each

Explanation:

Given data in the problem:

The triangle is a right triangle

thus,

one of the angle is 90°

now,

let the other two angles be x and y

thus,

it is given that:

x = 2y - 45°

also in a triangle

sum of all the angles = 180°

thus,

x + y + 90° = 180°

or

x + y = 90°

now, substituting the  value of x from the above relation between x and y, we get

2y - 45° + y = 90°

or

3y = 135°

or

y = 45°

also,

x = 2y - 45°

or

x = 2 × (45°) - 45°

or

x = 45°

hence, <u>the other two small angles are 45° each</u>

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Accelerating charges radiate electromagnetic waves. Calculate the wavelength of radiation produced by a proton of mass mp moving
Iteru [2.4K]

Explanation:

Let m_p is the mass of proton. It is moving in a circular path perpendicular to a magnetic field of magnitude B.

The magnetic force is balanced by the centripetal force acting on the proton as :

\dfrac{mv^2}{r}=qvB

r is the radius of path,

r=\dfrac{mv}{qB}

Time period is given by :

T=\dfrac{2\pi r}{v}

T=\dfrac{2\pi m_p}{qB}

Frequency of proton is given by :

f=\dfrac{1}{T}=\dfrac{qB}{2\pi m_p}

The wavelength of radiation is given by :

\lambda=\dfrac{c}{f}

\lambda=\dfrac{2\pi m_pc}{qB}

So, the wavelength of radiation produced by a proton is \dfrac{2\pi m_pc}{qB}. Hence, this is the required solution.

3 0
3 years ago
A 70 ft rope hangs from a helicopter above this room. The rope has a mass per unit length of 2 lb/ft. In order to be rescued fro
Mrac [35]

Answer:

The work done to get you safely away from the test is  2.47 X 10⁴ J.

Explanation:

Given;

length of the rope, L = 70 ft

mass per unit length of the rope, μ = 2 lb/ft

your mass, W = 120 lbs

mass of the 70 ft rope  = 2 lb/ft x 70 ft

                                         = 140 lbs.

Total mass to be pulled to the helicopter, M = 120 lbs  + 140 lbs  

                                                                       = 260 lbs

The work done is calculated from work-energy theorem as follows;

W = Mgh

where;

g is acceleration due gravity = 32.17 ft/s²

h is height the total mass is raised = length of the rope = 70 ft

W = 260 Lb x 32.17 ft/s²  x 70 ft

W = 585494 lb.ft²/s²

1 lb.ft²/s² = 0.0421 J

W = 585494 lb.ft²/s²  = 2.47 X 10⁴ J.

Therefore, the work done to get you safely away from the test is  2.47 X 10⁴ J.

4 0
2 years ago
What remains constant during the trajectory of an object
S_A_V [24]

Answer:

projectile

Explanation:

3 0
3 years ago
In the parallel spring system, the springs are positioned so that the 37 N weight stretches each spring equally. The spring cons
Reptile [31]

Answer:

x = 5.29 m

Explanation:

given,

weight of stretch = 37 N

left-hand spring constant (k₁)= 2.7 N/cm

right hand spring constant(k₂)= 4.3 N/ cm

spring are connected in parallel

F = F₁ + F₂

F = k₁x + k₂x

F = (k₁+ k₂)x

37= (4.3+ 2.7)x

7 x = 37

x = 5.29 m

3 0
3 years ago
A 40-cmcm-long tube has a 40-cmcm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. A
Licemer1 [7]

Answer:

1070 Hz

Explanation:

First, I should point out there might be a typo in the question or the question has inconsistent values. If the tube is 40 cm long, standing waves cannot be produced at 42.5 cm and 58.5 cm lengths. I assume the length is more than the value in the question then. Under this assumption, we proceed as below:

The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength \frac{\lambda}{2}.

Hence, we have

\dfrac{\lambda}{2}=58.5-42.5=16 \text{ cm}

\lambda=32\text{ cm}=0.32 \text{ m}.

The speed of a wave is the product of its wavelength and its frequency.

v=f\lambda

f=\dfrac{v}{\lambda}

f=\dfrac{343}{0.32}=1070 \text{ Hz}

7 0
3 years ago
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