Question

The circumference of the inner circle is 88 ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner​ circle? Use StartFraction 22 Over 7 EndFraction
for pi. (3.14)

Answer 1

Answer:

18.86 feet

Step-by-step explanation:

The circumference of the inner circle is 88 ft.

Circumference of a Circle$=2\pi r$

Therefore:

$2\pi r =88\\r=88 \div (2*\frac{22}{7})=14 ft$

Radius of the inner circle=14 feet

If the distance between the inner circle and the outer circle is 3 ft, the radius of the outer circle=14+3 =17 feet.

Therefore. circumference of the outer Circle$=2\pi r$

$=2*\frac{22}{7}*17=106.86 ft$

Difference in Circumference=106.86-88 =18.86 feet

The circumference of the outer circle is greater than that of the inner circle by 18.86 feet.