The circumference of the inner circle is 88 ft. The distance between the inner circle and the outer circle is 3 ft. By how many
1 answer:
Answer:
18.86 feet
Step-by-step explanation:
The circumference of the inner circle is 88 ft.
Circumference of a Circle
Therefore:
Radius of the inner circle=14 feet
If the distance between the inner circle and the outer circle is 3 ft, the radius of the outer circle=14+3 =17 feet.
Therefore. circumference of the outer Circle
Difference in Circumference=106.86-88 =18.86 feet
The circumference of the outer circle is greater than that of the inner circle by 18.86 feet.
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Answer:
No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R
Step-by-step explanation:
Assuming: the function is in [0,1]
And rewriting it for the sake of clarity:
Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer
1) A function is considered to be differentiable if, and only if both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:
2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]
The limit to the left
g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)
3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R
Because this is the same as to calculate the limit from the left and right side, of g(x).
This is what the Bilateral Theorem says: