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3 years ago

How many ( 1/8") in one inch?

Engineering

2 answers:

kotegsom [21]3 years ago

7 0

There would be 8 (1/8”th’s) in an inch.

Anna35 [415]3 years ago

4 0

Answer:

1 inch

Explanation:

There for there are 8 1/8 inch that make up 1 inch so the answer is 1 inch

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In the action adventure film Indiana Jones and the Raiders of the Lost Ark, Indiana Jones searches for the Ark of the Covenant.

zhuklara [117]

Answer:

hshhshuwuuwhhwbbdhuuduuwhbshbd ushwhhhsbdb hsuhsheuudhhe sujehhe

7 0

3 years ago

"It is necessary to select a metal alloy for an application that requires a yield strength of at least 345 MPa (50,000 psi) whil

nataly862011 [7]

Answer:

Both Brass and 1040 Steel maintain the required ductility of 20%EL.

Explanation:

Solution:-

- This questions implies the use of empirical results for each metal alloy plotted as function of CW% and Yield Strength.

- So for each metal alloy use the attached figures as reference and determine the amount of CW% required for a metal alloy to maintain a Yield Strength Y = 345 MPa.

- Left Figure (first) at Y = 345 MPa ( y -axis ) and read on (x-axis):

1040 Steel --------> 0% CW

Brass ---------------> 22% CW

Copper ------------> 66% CW

The corresponding ductility (%EL) for cold Worked metal alloys can be determined from the right figure. Using the %CW for each metal alloy determined in first step and right figure to determine the resulting ductility.

- Right Figure (second) at respective %CW (x-axis) read on (y-axis)

1040 Steel (0% CW) --------> 25% EL

Brass (22% CW) -------------> 21% EL

Copper (66% CW) ----------> 4% EL

We see that both 1040 Steel and Brass maintain ductilities greater than 20% EL at their required CW% for Yield Strength = 345 MPa.

4 0

4 years ago

Which is the correct order for handwashing

cupoosta [38]

Answer:

Follow these five steps every time.

1.Wet your hands with clean, running water (warm or cold), turn off the tap, and apply soap.

2.Lather your hands by rubbing them together with the soap. Lather the backs of your hands, between your fingers, and under your nails.

3.Scrub your hands for at least 20 seconds. Need a timer? Hum the “Happy Birthday” song from beginning to end twice.

4.Rinse your hands well under clean, running water.

5.Dry your hands using a clean towel or air dry them.

8 0

3 years ago

Read 2 more answers

Sea water with a density of 1025 kg/m3 flows steadily through a pump at 0.21 m3 /s. The pump inlet is 0.25 m in diameter. At the

myrzilka [38]

Answer:

$\dot W_{pump} = 16264.922\,W\,(16.265\,kW)$

Explanation:

The pump is modelled after applying Principle of Energy Conservation, whose form is:

$\frac{P_{1}}{\rho\cdot g}+ \frac{v_{1}^{2}}{2\cdot g} +z_{1} + h_{pump}=\frac{P_{2}}{\rho\cdot g}+ \frac{v_{2}^{2}}{2\cdot g} +z_{2}$

The head associated with the pump is cleared:

$h_{pump} = \frac{P_{2}-P_{1}}{\rho\cdot g}+\frac{v_{2}^{2}-v_{1}^{2}}{2\cdot g}+(z_{2}-z_{1})$

Inlet and outlet velocities are found:

$v_{1} = \frac{0.21\,\frac{m^{3}}{s} }{\frac{\pi}{4}\cdot (0.25\,m)^{2} }$

$v_{1} \approx 4.278\,\frac{m}{s}$

$v_{2} = \frac{0.21\,\frac{m^{3}}{s} }{\frac{\pi}{4}\cdot (0.152\,m)^{2} }$

$v_{2} \approx 11.573\,\frac{m}{s}$

Now, the head associated with the pump is finally computed:

$h_{pump} = \frac{175\,kPa-81.326\,kPa}{(1025\,\frac{kg}{m^{3}} )\cdot (9.807\,\frac{m}{s^{2}} )} +\frac{(11.573\,\frac{m}{s} )^{2}-(4.278\,\frac{m}{s} )^{2}}{2\cdot (9.807\,\frac{m}{s^{2}} )} + 1.8\,m$

$h_{pump} = 7.705\,m$

The power that pump adds to the fluid is:

$\dot W_{pump} = \dot V \cdot \rho \cdot g \cdot h_{pump}$

$\dot W_{pump} = (0.21\,m^{3})\cdot (1025\,\frac{kg}{m^{3}})\cdot (9.807\,\frac{m}{s^{2}})\cdot(7.705\,m)$

$\dot W_{pump} = 16264.922\,W\,(16.265\,kW)$

4 0

3 years ago

Three methods by which the value of the unknown resistance can be determined

Contact [7]

Answer:

The Meter bridge is the modification of Wheatstone's network used to determine the value of unknown resistance. The meter bridge consists of a thin, uniform, and homogenous conducting wire AC, rectangular wooden board between two thick L shaped metal strips C1 and C2 as shown in the diagram.

5 0

3 years ago