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Answer:
Explanation:
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the program is written thus;
#include<iostream>
using namespace std;
// function declaration
void rShift(int&, int&, int&, int&, int&, double&);
int main()
{
// declare the variables
int a1, a2, a3, a4;
int maximum = 0;
double average = 0;
// inputting the numbers
cout << "Enter all the 4 integers seperated by space -> ";
cin >> a1 >> a2 >> a3 >> a4;
cout << endl << "Value before shift." << endl;
cout << "a1 = " << a1 << ", a2 = " << a2 << ", a3 = "
<< a3 << ", a4 = " << a4 << endl << endl;
// calling rSift()
// passing the actual parameters
rShift(a1,a2,a3,a4,maximum,average);
// printing the values
cout << "Value after shift." << endl;
cout << "a1 = " << a1 << ", a2 = " << a2 << ", a3 = "
<< a3 << ", a4 = " << a4 << endl << endl;
cout << "Maximum value is: " << maximum << endl;
cout << "Average is: " << average << endl;
}
// function to right shift the parameters circularly
// and calculate max, average of the numbers
// and return it to main using pass by reference
void rShift(int &n1, int &n2, int &n3, int &n4, int &max, double &avg)
{
// calculating the max
max = n1;
if(n2 > max)
max = n2;
if(n3 > max)
max = n3;
if(n4 > max)
max = n4;
// calculating the average
avg = (double)(n1+n2+n3+n4)/4;
// right shifting the numbers circulary
int temp = n2;
n2 = n1;
n1 = n4;
n4 = n3;
n3 = temp;
}
The equations are based on the following assumptions
1) The bar is straight and of uniform section
2) The material of the bar is has uniform properties.
3) The only loading is the applied torque which is applied normal to the axis of the bar.
4) The bar is stressed within its elastic limit.
Nomenclature
T = torque (Nm)
l = length of bar (m)
J = Polar moment of inertia.(Circular Sections) ( m^4)
J' = Polar moment of inertia.(Non circluar sections) ( m^4 )
K = Factor replacing J for non-circular sections.( m^4)
r = radial distance of point from center of section (m)
ro = radius of section OD (m)
τ = shear stress (N/m^2)
G Modulus of rigidity (N/m^2)
θ = angle of twist (radians)
1) The bar is straight and of uniform section
2) The material of the bar is has uniform properties.
3) The only loading is the applied torque which is applied normal to the axis of the bar.
4) The bar is stressed within its elastic limit.
Nomenclature
T = torque (Nm)
l = length of bar (m)
J = Polar moment of inertia.(Circular Sections) ( m^4)
J' = Polar moment of inertia.(Non circluar sections) ( m^4 )
K = Factor replacing J for non-circular sections.( m^4)
r = radial distance of point from center of section (m)
ro = radius of section OD (m)
τ = shear stress (N/m^2)
G Modulus of rigidity (N/m^2)
θ = angle of twist (radians)