3 years ago

What does CADCAM stand for ?

Engineering

2 answers:

jekas [21]3 years ago

7 0

CAD-Computer-aided design

CAM-computer-aided manufacturing

tangare [24]3 years ago

4 0

It's for like computers

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The acceleration of a point is given. a = 20 t m/s2 When t=0, s = 50 m and v = -8 m/s. What are the position and velocity of the

lidiya [134]

Answer:

v=82 m/s

s=116m

Explanation:

a=20t

$\frac{\mathrm{d} v}{\mathrm{d} t}=20t\\\int\limits dv =\int(20t) dt\\v={10}t^2+c$

using condition given at t=0

$-8=10\times 0^2 +c$

c=-8

now equation becomes

v=10t²-8

v at t= 3s v=82 m/s

again

$\frac{\mathrm{d} s}{\mathrm{d} t}=10t^2-8$

$ds=(10t^2-8)dt\\\int\limits ds =\int(10t^2-8) dt\\s=\frac{10}{3} t^2-8t+b$

now using condition given s=50 at t=0

b=50

now equation becomes

$s=\frac{10}{3}t^3-8t+50$

calculating s at t=3s

s=116m

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2 years ago

Water is pumped from one large reservoir to another at a higher elevation. If the flow rate is 2.5 ft3 /s and the pump delivers

4vir4ik [10]

Answer:

2132hp ed enregia

Explanation:

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6 0

3 years ago

Someone please please help me and explain!! I will give brainliest if right!!!

Mariulka [41]

R=10+15+30

55 is the answer to the question

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2 years ago

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If you add 10 J of heat to a system so that the final temperature of the system is 200K, what is the change in entropy of the sy

Elden [556K]

Answer:

0.05 J/K

Explanation:

Given data in question

heat (Q) = 10 J

temperature (T) = 200 K

to find out

the change in entropy of the system

Solution

we will solve this by the entropy change equation

i.e ΔS = ΔQ/T ...................1

put the value of heat Q and Temperature T in equation 1

ΔS is the enthalpy change and T is the temperature

so ΔS = 10/200

ΔS = 0.05 J/K

8 0

2 years ago

If the contact surface between the 20-kg block and the ground is smooth, determine the power of force F when t = 4 s. Initially,

grigory [225]

Answer:

The power of force F is 115.2 W

Explanation:

Use following formula

Power = F x V

$F_{H}$ = F cos0

$F_{H}$ = (30) x 4/5

$F_{H}$ = 24N

Now Calculate V using following formula

V = $V_{0}$ + at

$V_{0}$ = 0

a = $F_{H}$ / m

a = 24N / 20 kg

a = 1.2m / $S^{2}$

no place value in the formula of V

V = 0 + (1.2)(4)

V = 4.8 m/s

So,

Power = $F_{H}$ x V

Power = 24 x 4.8

Power = 115.2 W

3 0

2 years ago