All categories

3 years ago

What is the value of m in the equation 4m + 2(m + 1) = 9m + 5? (4 points)

Mathematics

2 answers:

docker41 [41]3 years ago

7 0

I hope this helps you

4m+2.m+2.1=9m+5

6m+2=9m+5

9m-6m=2-5

3m= -3

m= -1

dalvyx [7]3 years ago

5 0

Answer: The value of 'm' is - 1.

Step-by-step explanation: We are given to find the value of 'm' from the following equation:

$4m+2(m+1)=9m+5.$

The solution is as follows:

$4m+2(m+1)=9m+5\\\\\Rightarrow 4m+2m+2=9m+5\\\\\Rightarrow 6m+2=9m+5\\\\\Rightarrow 6m-9m=5-2\\\\\Rightarrow -3m=3\\\\\Rightarrow m=\dfrac{3}{-3}\\\\\Rightarrow m=-1.$

Thus, the required value of 'm' is - 1.

You might be interested in

How do i do fifth grade divison

ser-zykov [4K]

Ummm like long division

6 0

3 years ago

Which dimensions cannot create a triangle? a three sides measuring 6 cm, 8 cm, and 10 cm b three angles measuring 40 degrees, 70

NISA [10]

Answer:

A,C,D are triangles, B is not.

Step-by-step explanation:

Let 3 sides of a triangle be a,b,c.

A triangle have the sum of 3 angles = 180 degree

and

a-b<c<a+b (similar for a and b)

a. three sides measuring 6 cm, 8 cm, and 10 cm

Satisfied the a-b<c<a+b property -> triangle

b. three angles measuring 40 degrees, 70 degrees, and 65 degrees

Total of 3 angles = 40+70+65 = 175 > 180

-> not triangle

c. three angles measuring 10 degrees, 25 degrees, and 145 degrees

Total of 3 angles = 10+25+145 = 180

-> triangle

d. three sides measuring 9 m, 15 m, and 9 m

Satisfied the a-b<c<a+b property -> triangle

7 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST Raul, Chris, and Jerry together sold 88 tickets for the school banquet. Raul sold 30 tickets, and Chris sol

zloy xaker [14]

Answer:

20 or B)

Step-by-step explanation:

88-30= 58

58-38= 20

Jerry sold 20

Hope this helped.

A brainliest is always appreciated.

8 0

2 years ago

Use the triangle below to find cos V.

Semenov [28]

Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

$cos V= \frac{TV}{UV}$

Where

$TV = 6$

and

$UV^2 = TV^2 + TU^2$ -- Pythagoras

$UV^2 = 6^2 + 15^2$

$UV^2 = 261$

Take square roots

$UV = \sqrt{261$

$UV = \sqrt{9*29$

$UV = \sqrt{9} *\sqrt{29$

$UV = 3\sqrt{29$

So:

$cos V= \frac{TV}{UV}$

$cos\ V = \frac{6}{3\sqrt{29}}$

$cos\ V = \frac{2}{\sqrt{29}}$

Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

$cos\ V = \frac{2\sqrt{29}}{29}$

8 0

3 years ago

Find the slope of the graphed line

Contact [7]

Answer:

slope = 3/5

Step-by-step explanation:

slope = rise/run = 3/5

or (longer way w/ the points)

slope = (y2-y1)/(x2-x1) = (5-2)/(4-(-1)) = 3/5

3 0

3 years ago