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3 years ago

Help me please its angle addition prostate 7x + 1 + x - 12 = -3

Mathematics

1 answer:

dlinn [17]3 years ago

6 0

Answer:

x=1

Step-by-step explanation:

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Please help me thanks.

daser333 [38]

y=(-2x)+5

Step-by-step explanation:

4 0

3 years ago

What is the factorization of the trinomial below? -X^2 - 2x + 48

raketka [301]

Answer:

<h3>I think option C.</h3>

(x-6) (x-8).

3 0

3 years ago

Read 2 more answers

Farrah borrowed $155 from her brother. She has already paid back $15. She plans to pay back $35 each month until the debt is pai

Sergeeva-Olga [200]

Answer:

4 months

Step-by-step explanation:

if she paid the 15 already subtract it from the 155. Once you that you get 140 and if you break that inton groups of 35 *division* than you get 4. As in 4 months

7 0

3 years ago

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Which one also whats 473+838=

Mashutka [201]

Answer:

1,311

Step-by-step explanation:

7 0

3 years ago

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The quadratic function g(x) = a.ca + bx+c has the

Mumz [18]

The value of b is 14 and the value of c is 65

<h2>Explanation:</h2>

The quadratic function is a function of the form:

$f(x)=ax^2+bx+c$

Here we know that the leading coefficient $a=1$ so we reduce our equation to:

$g(x)=x^2+bx+c$

The roots are those values at which $g(x)=0$

So:

$x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\ 49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\$

$Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\ 49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0$

So we have:

$(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}$

Finding c from (1):

$33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}$

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

5 0

3 years ago