The speed of wind and speed of plane in still air are 23 and 135
km/h respectively.
<u>Step-by-step explanation:</u>
Let the speed of wind and speed of plane in still air are w and p km/h respectively.
The effective speed on onward journey was
................(1)
The effective speed on return journey was
..............(2)
Adding equation (1) and equation (2) we get,
⇒ 
⇒ 
⇒ 
Putting value of in we get:
⇒
⇒ 
⇒ 
Therefore ,The speed of wind and speed of plane in still air are 23 and 135
km/h respectively.
Answer:
Step-by-step explanation:
This is a unit rate problem. If we want to find out how much chocolate was eaten in 1 minute, we divide 31.5 by 7. This gives us the number of ounces of chocolate eaten in 1 minute: 4.5 ounces per minute.
is that what you looking for
Answer:
The central angle of the sector is 0.5 radian
Step-by-step explanation:
given;
radius of the circle, r = 80 mi
area of the sector, A = 1600 mi²
Area of sector is given by;
A = ¹/₂r²θ
where;
θ is the central angle (in radians) of the sector
Therefore, the central angle of the sector is 0.5 radian
Answer:
<h2>
y = - 4x + 3</h2>
Step-by-step explanation:
Slope:
Point-slope frorm:
m = -4 ; point (0, 3) ⇒ x₀=0, y₀=3
y - 3 = - 4(x - 0)
y - 3 = - 4x
y = - 4x + 3 ← slope intercept form
