Question

The solubility of kL is 50g in 100 g h2o at 20 celcius. If 110 grams of of kL are added to 200 grams of h2o. What is happens ?

Answer 1

Answer:

a saturated solution will form.

Explanation:

All solutions have a definite capacity of dissolving solute in it.

Unsaturated solutions are the solutions which contain less amount of solute than the maximum capacity of dissolving the solute. If more amount of solute is added in such a way a point is reached where addition of more solute cannot be dissolved. The solution is known as saturated solution.

Amount dissolved > Maximum solubility limit, the solution is saturated.

Amount dissolved < Maximum solubility limit, the solution is unsaturated.

If the amount of the salt exceeds the solubility limit, then the solution is saturated solution. If it is less than the limit given, then it is unsaturated solution.

Given,

50 g of KI is added to 100 g of water at 20 °C.

It means:

100 g of water can dissolve maximum of 50 g of  KCl.

Also,

1 g of water can dissolve maximum of 0.5 g of  KCl.

To check for 200 g of water:

200 g of water can dissolve maximum of (0.5)*200 g of  KCl.

Maximum amount of KCl that can be dissolved = 100 g

Actual amount dissolved = 110 g

Since,

Amount dissolved > Maximum solubility limit

110 g > 100 g

According to definition, the solution is saturated.

Hence, a saturated solution will form.