A penny is 0.061 inches thick. What is the value of the 6 in the thickness of a penny? Mathematics not chemistry

Chemistry

2 answers:

Ivan3 years ago

5 0

Answer:

Hundredths

Explanation:

$6 times 1/$100. The 0 is tenths, the 6 is hundredths and the 1 is thousandths.

Norma-Jean [14]3 years ago

4 0

Answer:

because of the location of the 6 the answer is 6 cent

You might be interested in

You have two sealed jars of water at the same temperature. In the first jar there is a large amount of water. In the second jar

melisa1 [442]

since both the jars are kept at the same temperature the vapor pressure will be same in both the cases.

3 0

3 years ago

Select the correct answer.

Minchanka [31]

Answer:

A. it is the lowest at low temperatures

Explanation:

It is true with respect to the kinetic energy of a molecule that the it is the lowest at low temperatures.

The kinetic energy of a molecule is the energy due to the motion of the particles within a substance.

Kinetic energy is directly proportional to the temperature of a substance.
The higher the temperature, the more the kinetic energy of the molecules within a system.
At low temperature, kinetic energy is the lowest.
At the highest temperature, kinetic energy is the highest

3 0

3 years ago

Read 2 more answers

An experiment produced 0.10 g CO2 with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is th

Mandarinka [93]

The experimental density of CO2 at STP is 0.10/0.056=1.78 g/L. The percent error equals to (1.96-1.78)/1.96*100%=9.18%. So the answer is 9.18%.

3 0

3 years ago

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

scoray [572]

Answer:

70.77 g/mol is the molar mass of the unknown gas.

Explanation:

Effusion is defined as rate of change of volume with respect to time.

Rate of Effusion= $\frac{Volume}{Time}$

Effusion rate of oxygen gas after time t = $E=\frac{4.64 mL}{t}$

Molar mass of oxygen gas = M = 32 g/mol

Effusion rate of unknown gas after time t = $E'=\frac{3.12 mL}{t}$

Molar mass of unknown gas = M'

The rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$