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drek231 [11]
3 years ago
10

When a chemist collects hydrogen gas over water, she ends up with a mixture of hydrogen and water vapor in her collecting bottle

. If the pressure in the collecting bottle is 97.1 kilopascals and the vapor pressure of the water is 3.2 kilopascals, what is the partial pressure of the hydrogen?
Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

Answer: The partial pressure of the hydrogen gas is 93.9 kiloPascals.

Explanation:

The partial pressure of the water vapors = p_{H_2O,g}=3.2 kPa

The partial pressure of the hydrogen gas = p_{H_2}

The pressure measured in the collecting bottle  = p=97.1 kPa

While collecting the hydrogen gas in a collecting bottle with amount of water vapors also get introduced. The total pressure in the collecting bottle will be due to partial pressures of the water vapors and hydrogen.

p=p_{H_2O,g}+p_{H_2}

97.1 kPa=3.2 kPa+p_{H_2}

p_{H_2}=97.1 kPa-3.2 kPa=93.9 kPa

The partial pressure of the hydrogen gas is 93.9 kiloPascals.

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A 100.0 g sample of aluminum released 1680 calories when cooled from 100.0c to 20.0 c what is the specific heat of the metal
vovangra [49]

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The specific heat of aluminium is 0.8792 J/g °C  or 0.21 Cal/g °C

Explanation:

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Q=mcΔT

with Q = heat transfer (J)

with m = mass of the substance

with c = specific heat ⇒ depends on material and phase ( J/g °C)

with ΔT = Change in temperature

For this case :

Q = 1680 Calories = 7033.824 J ( 1 calorie = 4.1868 J)

m = 100.0g

c= has to be determined

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<u>Step 2:  Calculating specific heat</u>

⇒ via the formule Q=mcΔT

7033.824 J = 100g * c * 80

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c = 7033.824 /8000

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6 0
3 years ago
No spam or links! Thanks!
Monica [59]

Answer:

364 K or 91°C

Explanation:

Applying,

V₁/T₁ = V₂/T₂................ Equation 1

Where V₁ = Initial Volume, V₂ = Final volume, T₁ = initial Temperature, T₂ = final Temperature.

make T₂ the subject of the equation,

T₂ = V₂T₁/V₁................. Equation 2

From the question,

Given: V₁ = 375 mL, V₂ = 500 mL, T₁ = 0.0°C = (273+0) K = 273 K

Substitute these values into equation 2

T₂ = (500×273)/375

T₂ = 364 K

T₂ = (364-273) °C = 91 °C

5 0
3 years ago
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