Answer:
(a)
(b) v = 1064 m/s
Explanation:
(a) Frequency of electromagnetic wave,
Let is the wavelength of electromagnetic wave. It can be calculated as :
(b) Frequency of medium, f = 532 Hz
Wavelength,
Let v is the speed of sound wave in an unknown fluid. Using the relation as :
v = 1064 m/s
Hence, this is the required solution.
360.67 is the speed of waves on a violin string of mass 707 mg and length of 21.4 cm if the fundamental frequency is 867 Hz.
Mass per unit length of string н = mass/length
= 505×10⁻⁶ kg/ 0.204 m
= 2.47×10-³ kg/m
∫о
Fundamental frequency ∫о=884 Hz
a. Speed of waves v = 2L∫о
= 2×0.204 m x 884 Hz
=360.67 m/s.
For example, if the fundamental frequency is 50 Hz (also called the first harmonic), the second harmonic is 100 Hz (50 * 2 = 100 Hz), and the third harmonic is 150 Hz (50 * 3 = 150 Hz ). Such.
The fundamental frequency is the lowest frequency of the resonant system. This is an important concept in many aspects of musical instruments and engineering. For example, all harmonics of a particular wave are based on the fundamental frequency.
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Because the box keeps going straight at the same speed, while the seat under it speeds up, slows down, or changes direction.
The magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
<h3>What is force?</h3>
The force is an action of push or pull which makes a body to move or stop.
Given is the weight of tourist W = 805 N and L is the length of the bridge.
Let the reaction force at both the ends of the bridge is R1 and R2.
Taking the moments about point A,
R1 x 0 - W x L/4 +R2 x L =0
R2 = W/4
R2 = 805 /4
R2 = 201.25 N
Thus, the magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
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Answer:
Final angular velocity = 2.15rad/s
Explanation:
The final angular velocity can be determined using the equation:
L=Ii × wi
L= (Ii + II) × wf
Where I is the moment of inertia of the 2nd cylinder and wf is the final angular velocity.
Given:
Ii=12.6kgm^2
I=41.8kgm^2
Wi=9.28rad/s
Ii ×wi= (Ii + I)×wf
12.6×9.28 = (12.6+41.8)×wf
116.93= 54.4wf
Wf=116.93/54.4
Wf= 2.15rad/s