Explanation:
It is given that,
Mass of golf club, m₁ = 210 g = 0.21 kg
Initial velocity of golf club, u₁ = 56 m/s
Mass of another golf ball which is at rest, m₂ = 46 g = 0.046 kg
After the collision, the club head travels (in the same direction) at 42 m/s. We need to find the speed of the golf ball just after impact. Let it is v.
Initial momentum of golf ball, 
After the collision, final momentum 
Using the conservation of momentum as :


v = 63.91 m/s
So, the speed of the golf ball just after impact is 63.91 m/s. Hence, this is the required solution.
All answers to the Earth Science, Meteorology: Part 1 Unit Test
1. B. March 21
2. D. December 21
3. B. They move faster.
4. C. 300,000 kilometers per second
5. B. Conduction
6. A. longer than those emitted by the sun
7. D. Water vapor and carbon dioxide
8. C. Scattering
9. D. Both b and c
10. C. There is a greater percentage of water surface in the Sourhern Hemisphere
11. D. Both a and b
12. B. Absorbing outgoing radiation
13. D. Deposition
14. B. It contains more water vapor than cold air
15. D. Both a and b
16. D. All of the above
17. B. Subtropical high
18. B. Day and flows torad the land
19. Essay
20. Essay
21. Essay
22. Essay
Use the formula 1/2*I*w^2 where w is the angular speed and I is the rotaional inirtia (for disk it is .5*mass*radius^2).
The answer is C hope it helped
1.) temperature change, 2.) color change, 3.) gas formation