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Novosadov [1.4K]
2 years ago
7

Olivia wants to find out whether a substance will fluoresce. She says she should put it in a microwave oven. Do you agree with h

er? Why or why not?
Physics
2 answers:
andreyandreev [35.5K]2 years ago
4 0
Disagree.
Fluoresce objects will only glow when put under actual Ultraviolet light. This is due to the molecules becoming excited by the ultraviolet radiation.


Microwaves give micro-waves that are present in another spectrum of wave length and will not be able to fluoresce the molecules. If it’s not “ultra violet “.... it’s not going to glow.
konstantin123 [22]2 years ago
4 0

Answer:

Sample Response: I disagree with her because many substances show fluorescence under ultraviolet light, not microwaves.

Explanation:

You might be interested in
Which statement describes a property of a proton?
lesantik [10]

Answer:

They have no charge and are present in the nucleus of an atom. They have a negative charge and travel around the nucleus of an atom. They have a positive charge and travel around the nucleus of an atom

Explanation:

7 0
3 years ago
A car drives 90 meters north, then turns around and drives 120 meters south. What was its displacement and distance?
Rufina [12.5K]

Answer:

displacement= 30 m towards south, distance= 210m

Explanation:

Distance (scalar quantity) how much ground an object has covered.

Displacement (vector quantity) refers to how far out of place an object is it is the object's overall change in position.

Basically meaning for displacement the directions will be very key

D for Displacement

D= D1+D2

D=  120 (S) + 90 m (N)

Must be in same direction

D= 120 (S) + (-90 m) (S)

D= 30 m (S)

and for distance you are simply just adding how much distance they have covered

so d= d1+d2

d= 90m + 120m

d= 210m

3 0
2 years ago
g The electric power needs of a community are to be met by windmills with 40-m-diameter rotors. The windmills are to be located
Ksenya-84 [330]

Answer:

Explanation:

Given Data

The diameter of the wind mills is d = 40m

Velocity of the air is V = 6 m / s

Required power output is:  P ₀ = 2100 k W

Expression to calculate the exergy of the air is

E = V ² / 2

Substitute the value in above expression

E = ( 6 m / s ) ² / 2

E = 18 m ² / s ² x (1kJ/kg / 1000m²/s²)

E = 0.018 k J / k g

Expression to calculate the density of the air is

P v =m R T

m /v = P  /RT ⋯ ⋯( I )

Here  

m  is the mass of the air,  

v  is the volume of the air,  

P  is the atmospheric pressure,  

T  is the standard temperature at the atmospheric pressure and  

R  is the gas constant

As the density is

ρ = m /V

Substitute the value in expression (I)

ρ = 101  kP a /( 0.287 k J / k g ⋅ K ) ( 298 K )

ρ = 1.180 k g / m ²

Expression to calculate the mass flow rate is

m = ρ A V ⋯ ⋯ ( I I )

Here  A  is the area of the windmill

Expression to calculate the  A  is

A = π /4  d ²

Substitute the value in above expression

A = π /4 ( 40 m ²)

A = 1256.63 m ²

Substitute the value in expression (II)

m = ( 1.180 k g / m ³) ( 1256.63 m ²) ( 6 m / s )

m = 8896.94  k g / s

Expression to calculate the maximum power available to the windmill is

P w = m ( V ² /2 )

Substitute the value in above expression

P w = 8896.94  k g / s ( (6m/s)²/2 )

P w = 160144.92 W  × ( 1 W /1000 k W )

P w = 160.144 k W

Expression to calculate the number of windmills required is

n = P o /P w

Substitute the value in above expression

n=2100kw/160.144kw

n=13.11

8 0
3 years ago
Question 7 (1 point)
Temka [501]

Answer:

Forms over water, warm humid air mass, it's a polar air mass

Explanation: I think that's right sorry if it's not..

GL! :)

4 0
2 years ago
a star has a distance of 30 parsecs and a apparent magnitude of 3 --what would its absolute magnitude be?
Alborosie

The absolute magnitude of the star would be +5.

8 0
1 year ago
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