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3 years ago

PLEASE HELP! I WILL AWARD BRAINLIEST!

Mathematics

1 answer:

goblinko [34]3 years ago

7 0

For this, we will be putting 190 in the T variable to solve for the c variable. Our equation will look like this: $40c-0.05(40c)=190$

So firstly, foil -0.05(40c): $40c-2c=190$

Next, combine like terms: $38c=190$

Next, divide both sides by 38, and your answer should be c = 5.

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Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = e−4x, [0, 2] Yes, it does not m

Zigmanuir [339]

Answer:

(a) Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem.

(b) $c =0.51995$

Step-by-step explanation:

Given

$f(x) = e^{-4x};\ [0,2]$

Solving (a); Does the function satisfy M.V.T on the given interval

We have:

$f(x) = e^{-4x};\ [0,2]$

The above function is an exponential function, and it is differentiable and continuous everywhere

Solving (b): The value of c

To do this, we use:

$f'(c) = \frac{f(b) - f(a)}{b - a}$

In this case:

$[a,b] = [0,2]$

So, we have:

$f'(c) = \frac{f(2) - f(0)}{2 - 0}$

$f'(c) = \frac{f(2) - f(0)}{2}$

Calculate f(2) and f(0)

$f(x) = e^{-4x}$

So:

$f(2) = e^{-4*2} = e^{-8} = 0.00033546262$

$f(0) = e^{-4*0} = e^{0} = 1$

This gives:

$f'(c) = \frac{0.00033546262 - 1}{2}$

$f'(c) = \frac{-0.99966453738}{2}$

$f'(c) = -0.4998$

Note that:

$f'(x) = (e^{-4x})'$

$f'(x) = -4e^{-4x}$

This implies that:

$f'(c) = -4e^{-4c}$

So, we have:

$f'(c) = -0.4998$

$-4e^{-4c} =-0.4998$

Divide both sides by -4

$e^{-4c} =\frac{-0.4998}{-4}$

$e^{-4c} =0.12495$

Take natural logarithm of both sides

$\ln(e^{-4c}) =\ln(0.12495)$

$\ln(e^{-4c}) =-2.0798$

Apply law of natural logarithm

$\ln(e^{ax}) =ax$

So:

$-4c =-2.0798$

Solve for c

$c =\frac{-2.0798}{-4}$

$c =0.51995$

3 0

3 years ago

Please some help me . OPTIONS: 75 degrees, 30, 90, or 45

lyudmila [28]

Answer:

x = 45

Step-by-step explanation:

x + 45 + 2x = 180

3x + 45 = 180

3x = 135

x = 45

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3 years ago

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Rzqust [24]

Answer:

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Step-by-step explanation:

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3 years ago

Yesterday, Tammy went on a bike ride. Her average speed was 8 miles per hour. Today, she went on another ride, this time averagi

Stels [109]

Answer:

y=120-4x

Step-by-step explanation:

Here we are given the average speed for Day 1 and Day 2 and the time of ride . We asked to Find an expression to determine the total distance travelled in two days.

Day 1 :

Avg Speed = 8 mph

Let the time for travelling = x hrs

Hence Distace Travelled D1= Speed x Time

D1=8x

Day 2 :

Avg Speed = 12 mph

Total time of travelling for two days is given as 10 hours . Hence the time of travelling for day 2 is

= (10-x) hrs

Hence Distance travelled in Day 2 D2 = speed x time

D2 = 12(10-x)

D2=120-12x

Total Distance travelled = D1 + D2

= 8x+120-12x

=120-4x

If the total distance travelled is denoted by y

The expression will be

y=120-4x

5 0

3 years ago

Find the degree of the polynomial below. 9x2 – 25

bulgar [2K]

Answer:

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2 years ago

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