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3 years ago

PLEASE HELP! I WILL AWARD BRAINLIEST!

Mathematics

1 answer:

goblinko [34]3 years ago

7 0

For this, we will be putting 190 in the T variable to solve for the c variable. Our equation will look like this: $40c-0.05(40c)=190$

So firstly, foil -0.05(40c): $40c-2c=190$

Next, combine like terms: $38c=190$

Next, divide both sides by 38, and your answer should be c = 5.

Looking at our chart, the best quality of editing that Ellen can do is C. Extended Proofreading.

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Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti

almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

$d=v.t$

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

$d=(x+y).t_1$

Where t1=2.5 hours. Substituting values:

$20=(x+y)*2.5$

Rearranging, we find the downstream equation:

$2.5x+2.5y=20\qquad[1]$

The speed when rowing upstream is x-y, and the distance traveled is

$d=(x-y).t_2$

Where t2=5 hours. Substituting values:

$20=(x-y)*5$

Rearranging, we find the upstream equation:

$5x-5y=20\qquad[2]$

Multiplying [1] by 2:

$5x+5y=40$

Adding this equation to [2]:

$10x=60$

Solving:

$x=60/10=6$

Dividing [2] by 5:

$x-y=4$

Solving for y

$y=x-4=6-4=2$

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

3 0

4 years ago

Write an equation for the function that includes the following points (2, 32) and (3, 64)

luda_lava [24]

Answer:

y=32x-32

Step-by-step explanation:

this time no algorithm or equation was needed i saw that if the equation was y=32x there would be ordered pairs (1,32) and (2,64) so to delay it by 1 on the x side just subtract the slope from the y - intercept sorry if that doesn't make sense

6 0

3 years ago

The length of a rectangular deck is 4 times its width if the decks perimeter is 30 ft, what is the decks area

omeli [17]

Answer:

The area of the rectangular deck is 36 sq feet.

Step-by-step explanation:

Let the width of the deck = k ft

So, the length of the deck = (4k) ft

Now, perimeter = 30 ft

PERIMETER OF A RECTANGLE = 2(LENGTH + WIDTH)

⇒2( k + 4k) = 30

or, 2 x 5k = 30 ⇒ 10k = 30

⇒ k = 30/10 = 3

So, the width of the deck = k = 3 ft

Length of the deck = 4k = 3 x 4 = 12 ft

Now, AREA OF A RECTANGLE = LENGTH X WIDTH

So, the area of the rectangular deck = 3 ft x 12 ft

= 36 sq feet

Hence, the area of the rectangular deck is 36 sq feet.

8 0

3 years ago

Malaya is making a collage of her birthday party photos and she wants to add an 8 x 10 inch. photo. Since there is not enough sp

sergij07 [2.7K]

Answer:

The answer is C. 6.4 X 8 in

Step-by-step explanation:

If the scale factor from the original to the trimmed photo is 5:4

The statement above just means the scale of the old dimension is 5 while the scale of the new dimension is 4.

To get the new dimensions, multiply each of the old dimensions by 4/5

4/5 X 10 = 8

4/5 X 8 = 6.4

Therefore the new dimension is 6.4 X 8 in

3 0

4 years ago

!PLEASE HELP ME!

yaroslaw [1]

Ok I think it b that’s what I think if it’s not that try C

5 0

3 years ago