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Elena L [17]
2 years ago
6

BC is tangent to circle A. Determine the length of AC . ANSWERS: 1) 3 2) 4 3) 5 4) 6

Mathematics
1 answer:
umka2103 [35]2 years ago
4 0
Answer:

3) 5

Explanation:

Use Pythagoras Theorem where

a^2 + b^2 = c^2

3^2 + 4^2 = 25

C= root 25 = 5
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The lunch special at Scott's Restaurant is a sandwich, a drink and a dessert. There are 3 sandwiches, 1 drink, and 2 desserts to
mash [69]

Answer:

24 for being able to not have one, 6 for having one of each

Step-by-step explanation:

multiplication

with the option of none

4*2*3=24

without the option of none

3*1*2=6

4 0
2 years ago
30 points please help on these questions!
hichkok12 [17]

Answer:

‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎

5 0
2 years ago
FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
Hi can anyone help me with this please
Nostrana [21]

Answer:35in.

Step-by-step explanation:

I reccomend splitting it into sections when given problems like this.

The smaller two rectangles would be 5in * 2in which is 10in then just add them together.

For the bigger one, you'd do 5-2 in order to get the missing inches which will be 3+2 once added 5in*3in is 15in.

Finally, add 15+10+10 (15=The middle rectangle and 10=the sides)

8 0
3 years ago
Read 2 more answers
Solve 4 brainliest xx
irga5000 [103]
C is on the line and D is not on the line.
-1/2(-40)+1=21
-1/2(20)+1≠-11
5 0
2 years ago
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