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3 years ago

Which type of nuclear energy involves splitting atoms

1 answer:

7 0

That would be nuclear fission. This occurs at a rapid level in the Atom Bomb. That is a chain reaction causing an explosion whereas the nuclear fission that occurs in a nuclear reactor is controlled.

You might be interested in

________ are solutions containing ions that react with acids or bases to minimize their effects.

myrzilka [38]

ions are solutions containing ions that react with acids or bases to minimize their effects.

6 0

3 years ago

Describe a polyhydroxyl alcohol.

Mademuasel [1]

With a name like poly hydroxyl alcohol, it suggests that the alcohol has more than one alcohol group. Thus any alcohol with more than one hydroxyl is a polyhydroxyl alcohol. An example that pops into mind is ethanediol (CH2OHCH2OH) this has 2 hydroxyl groups and is an alcohol, thus a polyhydroxyl alcohol

8 0

3 years ago

How many moles are present in 54.8 mL of mercury if the density of mercury is 13.6 g/mL?

lesya692 [45]

Answer:

3.72 mol Hg

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Density = Mass over Volume

Explanation:

Step 1: Define

D = 13.6 g/mL

54.8 mL Hg

Step 2: Identify Conversions

Molar Mass of Hg - 200.59 g/mol

Step 3: Find

13.6 g/mL = x g / 54.8 mL

x = 745.28 g Hg

Step 4: Convert

$745.28 \ g \ Hg(\frac{1 \ mol \ Hg}{200.59 \ g \ Hg} )$ = 3.71544 mol Hg

Step 5: Check

We are given 3 sig figs. Follow sig fig rules and round.

3.71544 mol Hg ≈ 3.72 mol Hg

8 0

3 years ago

Convert the scientific notation to a decimal number. Type the correct answer in the box. 4 × 10-5 cm = cm

MakcuM [25]

Answer:

$4 * 10^{-5}cm = 0.00004cm$

Explanation:

Given

$4 * 10^{-5}cm = [\ ]cm$

Required

Solve

Apply law of indices

$4 * \frac{1}{10^5}cm = [\ ]cm$

Evaluate 10^5

$4 * \frac{1}{100000}cm = [\ ]cm$

$4 * 0.00001cm = [\ ]cm$

$0.00004cm = [\ ]cm$

Hence:

$4 * 10^{-5}cm = 0.00004cm$

3 0

3 years ago

For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this

Salsk061 [2.6K]

The following are the steps to complete and balnce the equation for the given reaction

Explanation:

We are given, NO2– is oxidized to NO3– and Ag is reduced to Ag

NO2– + Ag+ -----> NO3– + Ag(s)

Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3 N = +5

O = -2 O = -2

Ag = +1 Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

NO2– -----> NO3–

Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

NO2– + H2O -----> NO3–

Ag+ -----> Ag(s)

Step 4) Balance the H by adding H+

NO2– + H2O -----> NO3– + 2H+

Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

NO2– + H2O -----> NO3– + 2H+ + 2e-

Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

NO2– + H2O -----> NO3– + 2H+ + 2e-

2 Ag+ + 2e------> 2 Ag(s)

3 0

3 years ago