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Katarina [22]
3 years ago
7

Use the periodic table to choose the correct name for each of the following substances. Check all tha

Chemistry
1 answer:
Vinvika [58]3 years ago
8 0

Answer:

phosphorus trichloride

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Read 2 more answers
Which of the following best describes an empirical formula?
Monica [59]

Answer:

Option C :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

Explanation:

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

Tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule

For Example

      C₂H₆O₂ Consist of  Carbon (C), Hydrogen (H), and Oxygen (O)

Now

Look at the ratio of these three atoms in the compound

                         C : H : O

                         2 : 6 : 2

Divide the ratio by two to get simplest ratio

                          C : H : O

                         2/2 : 6/2 : 2/2

                             1 : 3 : 1

So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1

So the empirical formula will be

                     Empirical formula of C₂H₆O₂ = CH₃O

So, Option C is correct :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

6 0
3 years ago
Use bond energies from Table 10.3 in the textbook to estimate the enthalpy change (ΔH) for the following reaction. C2H2(g)+H2(g)
Digiron [165]

Answer: =176.6kJmol^{-1}

Explanation:Bond energy of H-H is 436.4 kJ/mole

Bond energy of  C-H is 414 kJ/mol

Bond energy of C=C is 620 kJ/mol

Bond energy of C≡C is 835 kJ/mol

\Delta H= {\text {sum of bond energies of reactants}}-  {\text {sum of bond energies of products}}

\Delta H= {1B.E(C≡C)+2B.E(C-H) +1B.E(H-H)} - {1B.E(C=C)+4B.E(C-H)}

\Delta H= {1B.E(835kJmole^{-1})+2B.E(414kJmole^{-1}) +1B.E(436.4kJmole^{-1})} -  {1B.E(620kJmole^{-1})+4B.E(414kjmole^{-1})}

=176.6kJmol^{-1}







7 0
3 years ago
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