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2 years ago

A glass tube contains mercury. What would be the height of the column of mercury which would create pressure equal to 1.00 atm

1 answer:

7 0

Since 1.00 atm is equal to 760 mmHg, the height of the column of mercury which would create pressure equal to 1.00 atm is 760 mm or 76 cm

<h3>What are the units of pressure?</h3>

Pressure is defined as the force acting perpendicularly per unit area of a surface.

The units of pressure include;

millimetres of mercury, mmHg
aatmospheres, atm,
pascals, Pa
Newtons per square metre, N/m^2

1 atmosphere is equal to 760 mmHg.

Therefore, the height of the column of mercury which would create pressure equal to 1.00 atm is 760 mm or 76 cm

Learn more about pressure at: brainly.com/question/25934121

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A baby weighs 7 pounds, 4 ounces at birth and 7 pounds, I ounce at discharge. What percent of weight did the baby lose

Aloiza [94]

Answer:

2.6%

Explanation:

As, 1 ounce (oz) = 0.0625 pounds (lb)

Therefore, weight of baby at discharge = 7 lb,1 oz = 7+0.0625 lb = 7.0625 lb

Since, 1 oz = 0.0625 lb

⇒ 4 oz = 4×0.0625 = 0.25 lb

Therefore, weight of baby at birth = 7 lb,4 oz = 7+0.25 lb = 7.25 lb

The amount of weight lost is equal to the difference of weight of the baby at birth and discharge.

Therefore, weight lost = 7.25 lb - 7.0625 lb = 0.1875 lb

Now, the percentage of weight lost by the baby is given by the amount of weight lost divided by the weight of the baby at birth.

Therefore, the percentage of weight lost = weight lost ÷ weight at birth = 0.1875 lb ÷ 7.25 lb × 100 = 2.6%

6 0

3 years ago

Consider the following reaction:

adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

2H₂O₂ ⟶ 2H₂O + O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

d[H₂O]/dt = 2d[O₂]/dt = 2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = 6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂

(a) Initial moles of H₂O₂

$\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }$

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

$\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }$

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

$\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}$

8 0

3 years ago

What is the enthalpy of combustion (per mole) of C4H10 (g)?

Artemon [7]

The balanced chemical reaction for the complete combustion of C4H10 is shown below:

C4H10 + (3/2)O2 --> 4CO2 + 5H2O

The enthalpy of formation are listed below:
C4H10: -2876.9 kJ/mol
O2: none (because it is pure substance)
CO2: -393.5 kJ/mol
H2O: -285.8 kJ/mol

The enthalpy of combustion is computed by subtracting the total enthalpy formation of the reactants from that of the products.

ΔHc = (4)(-393.5 kJ/mol) + (5)(-285.8 kJ/mol) - (-2876.9 kJ/mol)
= -126.1 kJ

Thus, the enthalpy of combustion of the carbon is -126.1 kJ.

5 0

2 years ago

Read 2 more answers

1 x 10^-3 m is the same as which of the following? Select all that apply.

Yuri [45]

Answer: b and d

Explanation:

1×10^-3=1×1/10³=1×1/1000=1/1000 so b is correct

1×10^-3=1/1000=0.001

so d is correct

8 0

2 years ago

A sperm cell from a male cat contains 19 chromosomes. When it reproduces with a female cat, how many chromosomes in total will a

Ilya [14]

Answer:

Explanation:

it is impossible that there is only sperm .egg must be present from female

19 from male and 19 from female

it is correct

dog has 76 chromosomes

if cat has it will be abnormal due to unequal chromosome

152

also not possible

3 0

2 years ago