Answer:
x=1
Step-by-step explanation:
According to your typed question,
f(x)=2x-3
Let f(x)=y
y=2x-3
Now,
Interchanging the positions of x and y
x=2y-3
x+3=2y
x+3/2=y
f'(x)=x+3/2
Then,
f(x)=f'(x)
2x-3=x+3/2
2(2x-3)=x+3
4x-3=x+3
4x-x=3+3
3x=3
x=3/3
x=1
According to your image question,
f(x)=x/2x-3
f(x)=f'(x)
Now,
Let y=f(x)
y=x/2x-3
y(2x-3)=x
2xy-3=x
2xy-x=3
x(2y-1)=3
2y-1=3x
2y=3x+1
y=3x+1/2
f'(x)=3x+1/2
Then,
f(x)=f'(x)
x/2x-3=3x+1/2
2x=6xsq+2x-9x+3
2x=6xsq+7x+3
solve for x ok
9514 1404 393
Answer:
none
Step-by-step explanation:
No work is required to maintain an object at a constant speed with no change in direction. Work is only done when an object is accelerated, or moved some distance in the direction of the net force applied.
you would do no work
Answer:
8 3/5
false
Step-by-step explanation:
Answer:
do ur test by ur own understanding... xD
Step-by-step explanation:
<h3>all the natural numbers can be expressed in the form of the product of its prime factors.</h3>
Using the side of the square find the area:
Area = 30^2 = 900 square feet.
The rectangles area is the same, 900 square feet.
Let the width = X
The length would be 2X + 70
Area = length x width
X * 2x+ 70 = 900
This expands to 2x^2 * 70x = 900
Use the quadratic formula to solve for x:
-70 +/- sqrt(70^2-4*2(-900))/2*2
X = 10
Width = x = 10 feet
Length = 2x + 70 = 90 feet
