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Minchanka [31]
3 years ago
9

A satellite orbiting the earth is directly over a point on the equator at 12:00 midnight every four days. It is not over that po

int at any time in between.Part AWhat is the radius of the satellite's orbit?
Physics
1 answer:
Mrrafil [7]3 years ago
5 0

Answer:

106417026.88435 m

Explanation:

T = Time period of the satellite = 4 days

m = Mass of the Earth =  5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Time period is given by

T=2\pi\sqrt{\dfrac{r^3}{GM}}\\\Rightarrow r=\left(\dfrac{T^2GM}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=\left(\dfrac{(4\times 24\times 60\times 60)^2\times 6.67\times 10^{-11}\times 5.972\times 10^{24}}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=106417026.88435\ m

The radius of the satellite's orbit is 106417026.88435 m

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