To calculate the net force of the car during the given time, we first need to calculate its acceleration, and then, use Newton's Second Law equation to calculate the net force.

We can calculate the acceleration of the car during the given tieme using the following equation:

$a=\frac{v-v_{o}}{time}$

Substituting the given information, we have:

$a=\frac{30\frac{m}{s} -15\frac{m}{s} }{10s}=\frac{15\frac{m}{s} }{10s}=1.5\frac{m}{s^{2} }$

Now that we have calculated the acceleration, we can calculate the net force:

$Force=mass*acceleration\\\\Force=4000kg*1.5\frac{m}{s^{2}}=6000\frac{kg.m}{s^{2}}=6000N$

Hence, we have that the net force is equal to 6000N.

Have a nice day!

3 0

3 years ago

A projectile is launched at an angle above the

erica [24]

If we neglect friction/air resistance, then the horizontal component
doesn't change, and the vertical component becomes (9.8 m/s downward)
greater each second thanks to gravity.

So, after 2 seconds, the horizontal component is still 40 m/s, and the
vertical component is (30 - 2·9.8) = 10.4 m/s upward.

Choice #1 says this.

7 0

3 years ago

A spring is hung vertically with a 425g mass attached to it. The mass is at rest. If the mass causes the spring to stretch 0.67

ivann1987 [24]

Answer:

6.22 N/m

Explanation:

F=xk Making k the subject of the formula then

$k=\frac {F}{x}$