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jonny [76]
3 years ago
11

The following equation defines f(x)=-3x-5 . If (-5,n) is an ordered pair of the function rule, what is the value of n?

Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

Given:

The function is

f(x)=-3x-5

(-5,n) is an ordered pair of the function rule.

To find:

The value of n.

Solution:

If (-5,n) is an ordered pair of the function rule, then the function must be satisfied by the point (-5,n). It means f(-5)=n.

Substitute x=-5 in the given function.

f(-5)=-3(-5)-5

f(-5)=15-5

f(-5)=10

We know that, f(-5)=n. So,

n=10

Therefore, the value of n is 10.

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y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

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