The amount of substance left of a radioactive element of half life,
after a time, t, is given by:
Given that <span>potassium-40 has a half life of approximately 1.25 billion
years.
The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:
Therefore, </span><span>the maximum age of a fossil that we could date using 40k is
12.5 billion years.</span>
Answer:
Side 1 = 8, side 2=6, side 3=3 1/3 or 10/3
Step-by-step explanation:
We can set up a proportion comparing the sides of the original triangle to the new triangle.
The original triangle has sides 12, 9, and 5. The new triangle has sides 8, e, and f (use whatever letters you like, it doesn't matter, but for me, e is the side with the middle length and f is the side with the shortest length.
We can write 3 ratios, with the length of the new triangle over the length of the old triangle.
8/12 e/9 f/5
To figure out e and f, put each ratio equal to 8/12.
<u>8 </u> = <u>e</u> Then multiply both sides of the equation by 9 and get <u>72 </u> = e, 6=e.
12 9 12
<u>8 </u> = <u>f </u> Then multiply both sides of the equation by 9 and get <u>40 </u> = f, <u>10</u>=f.
12 5 12 3
10/3 can be rewritten as 3 1/3.
Answer:
-(2)x+2
Step-by-step explanation:
g(x)=F(x)+2
g(x)=-(2)x+2
Answer:
71°
ineedatleast20characters:)
Answer:
0.1150 = 11.50% probability that the sample does not contain any fibers of polymer B
Step-by-step explanation:
Hypergeometric distribution:
The probability of x sucesses is given by the following formula:
In which:
x is the number of sucesses.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
In this question:
Fibers are chosen without replacement, which means that we use the hypergeometric distribution.
92 fibers means that
Sample of 10 means that
No polymeter B which means that
17 fibers of polymeter B which means that
a. What is the probability that the sample does not contain any fibers of polymer B
This is P(X = 0).
0.1150 = 11.50% probability that the sample does not contain any fibers of polymer B